Calculating Emitter, Base and Collector Currents in an NPN Transistor

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The emitter current in the NPN transistor is given as 8 mA, with 0.8% of minority carriers recombining in the base. To find the base current (IB) and collector current (IC), the relationship IE = IB + IC can be used. By substituting the known values into this equation, IB can be calculated as 0.8% of IC. This leads to the determination of alpha (α), which represents the common base current gain. The discussion highlights the importance of understanding these relationships in transistor operation.
cowgiljl
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The emitter current in a certian npn transitor is 8 mA. If .8% of the minority carrier injected into the base recombing with the holes, find the base current , collector current and the exact value of alpha

i am not sure how to get this started

thanks

joe
 
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still struggling and REALLY don't know how to go about this problem

thanks
joe
 
As you know IE = IB + IC
From the text I would gess that IB = 0.8% from IC, so just substitute in the first equation and you should find alpha
 
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