Transistors: Collector vs Emitter (where does the symmetry get broken)

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Discussion Overview

The discussion revolves around the distinctions between the collector and emitter in transistors, particularly focusing on the physical differences that break the perceived symmetry of these devices. Participants explore the implications of doping levels and junction behavior in both active and reverse bias conditions.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants express that transistors are not symmetrical, highlighting that the collector is lightly doped while the emitter is heavily doped, which affects their operational characteristics.
  • It is noted that the lighter doping of the collector leads to a wider depletion region, which allows for effective charge collection under reverse bias conditions.
  • Participants mention that if the collector and emitter were symmetrically doped, transistors would struggle to operate at voltages above 4 to 5 volts.
  • There is a discussion about the role of heavy doping in the emitter to enhance injection efficiency, particularly in npn transistors, where the majority of current is carried by electrons from the emitter rather than holes from the base.
  • A participant references a cross-section image of a BJT to illustrate the asymmetries in geometry and doping, suggesting that visual aids can clarify these distinctions.

Areas of Agreement / Disagreement

Participants generally agree that there are significant differences between the collector and emitter due to doping levels and their effects on transistor operation. However, the extent and implications of these differences remain a topic of exploration and debate.

Contextual Notes

The discussion includes assumptions about the operational conditions of transistors, such as the effects of doping on voltage handling and current gain, which may not be universally applicable across all transistor types or configurations.

aeftimia
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I thought I had a good understanding of transistors, but I have seen articles on how to tell the collector from the emitter. I had always pictured transistors as a perfectly symmetrical device. Either side could be the collector, and the opposite side was the emitter. Clearly, there is some subtlety I am missing.

So what physically makes the collector and emitter distinct?
 
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iThey is no way it is symetrical. Collector is very lightly doped and emitter is heavily doped. That's the reason collector base junction can take a larger reverse voltage. You can make the device work like a transistor if you reverse the C and E, but it don't not work very well.
 
If it was perfectly symmetrical, both active and reverse bias regions would be identical.

Collector is very lightly doped because, after reverse biasing the base-collector, you can "collect" charge carries over that very large depletion region.

Remember: lighter doping, wider depletion region.
 
Bassalisk said:
If it was perfectly symmetrical, both active and reverse bias regions would be identical.

Collector is very lightly doped because, after reverse biasing the base-collector, you can "collect" charge carries over that very large depletion region.

Remember: lighter doping, wider depletion region.

The lighter doping (and hence wider depletion region on the collector side of the CB junction) is, as yungman said, to increase the reverse breakdown voltage of the CB junction.

Even low power general purpose BJT's are usually designed for a CB reverse bias voltage of around 30 too 40 volts, with higher voltage devices requiring several hundred volts or more. Remember that under normal forward bias (active region) operation the CB junction is in fact reverse biased. If the same doping was used on the collector as was used on the emitter, most transistors would be unable to operate at much more than about 4 to 5 volts (Vce).

For the emitter, the higher levels of doping are used to increase the injection efficiency. For example, in an npn transistor, the heavy n+ doping in the emitter causes the vast majority of current across the BE junction to be electrons emitted from the n side (the emitter) rather than holes emitted from the base. Any holes emitted from the base are just "wasted" current, contributing to base current but contributing nothing collector current, and hence greatly reducing current gain.
 
Last edited:
It's helpful to look at the cross section of an actual BJT like in the image below:
http://www.allaboutcircuits.com/vol_3/chpt_2/8.html#03302.png

As you can see there are asymmetries in both the geometry and the doping.
 

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