Transition matrix between two bases?

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The discussion revolves around finding the transition matrix A from the basis So = {v1, v2, v3, v4} to the basis S = {u1, u2, u3, u4}. The vectors in S are expressed as linear combinations of the vectors in So, leading to the equation u = T*v, where T is the transition matrix. To find A, the inverse of T must be calculated, which can be done by setting up an augmented matrix [T|I] and performing row operations to achieve [I|T^{-1}]. There is some confusion regarding the setup and calculations, but the process involves using the coefficients from the linear combinations directly. Understanding this method will help in accurately determining the transition matrix.
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Homework Statement


Let So = {v1,v2,v3,v4} be basis of vector space V.
And S = {u1,u2,u3,u4} be set of vectors defined as follows:
u1 = 20v1 + 46v2 + 116v3 + 170v4
u2 = 20v1 + 86v2 + 147v3 + 174v4
u3 = 30v1 + 89v2 + 59v3 + 81v4
u4 = 15v1 + 27v2 + 12v3 + 9v4

Find transition matrix A from So to S which is transition matrix from S coordinates to So coordinates.



Homework Equations


I know how to find transition matrix, it's hard to explain put you want to but one basis down and the other basis next to it and turn one into identity matrix.



The Attempt at a Solution



So first off we know that S is a basis of vector space V since it just scalar multiples of So.

I have calculated transition for small basis like {(1,2),(2,1)} but am unsure how to set up for this problem

If someone can set it up for me or give advice on what to do I can solve it. Thanks in advance!
 
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You're given S=\vec{u} in terms of the basis S_0=\vec{v}. Or:

<br /> \begin{pmatrix}u_1\\u_2\\u_3\\u_4\end{pmatrix}=\begin{pmatrix}20 &amp;&amp; 46 &amp;&amp; 116 &amp;&amp; 170\\20 &amp;&amp; 86 &amp;&amp; 147 &amp;&amp; 174\\30 &amp;&amp; 89 &amp;&amp; 59 &amp;&amp; 81\\15 &amp;&amp; 27 &amp;&amp; 12 &amp;&amp; 9\end{pmatrix}\begin{pmatrix}v_1\\v_2\\v_3\\v_4\end{pmatrix}<br />

Which can be written more compactly:

<br /> \vec{u}=T\vec{v}<br />

Where T is the transition matrix from S_0 coordinates to S coordinates. I hope this helps!
 
electricspit said:
You're given S=\vec{u} in terms of the basis S_0=\vec{v}. Or:

<br /> \begin{pmatrix}u_1\\u_2\\u_3\\u_4\end{pmatrix}=\begin{pmatrix}20 &amp;&amp; 46 &amp;&amp; 116 &amp;&amp; 170\\20 &amp;&amp; 86 &amp;&amp; 147 &amp;&amp; 174\\30 &amp;&amp; 89 &amp;&amp; 59 &amp;&amp; 81\\15 &amp;&amp; 27 &amp;&amp; 12 &amp;&amp; 9\end{pmatrix}\begin{pmatrix}v_1\\v_2\\v_3\\v_4\end{pmatrix}<br />

Which can be written more compactly:

<br /> \vec{u}=T\vec{v}<br />

Where T is the transition matrix from S_0 coordinates to S coordinates. I hope this helps!
Okay so then I should take inverse of the T to find transition matrix?
 
Yes. You should be able to use:

<br /> \vec{u}=T\vec{v}<br />

To show that. It should take 1 line.
 
electricspit said:
Yes. You should be able to use:

<br /> \vec{u}=T\vec{v}<br />

To show that. It should take 1 line.
i just did thst, but apparently my answer was wrong. can you explain exactly the process? Do I use the numbers in the exact order you set up?
 
Make the augmented matrix:

<br /> A = [T|I]<br />

and do elementary row operations until you get:

<br /> B = [I|T^{-1}]<br />

Where I is the identity matrix. Does that help?
 
Last edited:
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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