- #1

- 3

- 0

Is there a way of transposing the formula to calculate the width (W) from a known height (H) and hydraulic diameter (Dh)?

Dh = (2xWxH)/(W+H)

Many thanks

Jon

- Thread starter Xpind
- Start date

- #1

- 3

- 0

Is there a way of transposing the formula to calculate the width (W) from a known height (H) and hydraulic diameter (Dh)?

Dh = (2xWxH)/(W+H)

Many thanks

Jon

- #2

Doc Al

Mentor

- 45,029

- 1,329

Multiply both sides by (W+H):Dh = (2xWxH)/(W+H)

(W+H)*Dh = 2*W*H

Now just multiply out the left hand side. And so on.

- #3

- 3

- 0

It's been a long time since I've needed to do this kind of thing, and at the moment I just can't see 'it' to isolate the width

I have four pages of re-written equations, unfortunately none of them start W=

Could you help a simpleton out, and finish the transposition through?

Thanks again

Jon

- #4

Doc Al

Mentor

- 45,029

- 1,329

(W+H)*Dh = 2*W*H

Now just multiply out the left hand side:

W*Dh + H*Dh = 2*W*H

Collect terms with W to one side:

2*W*H - W*Dh = H*Dh

W*(2*H - Dh) = H*Dh

So:

W = H*Dh/(2*H - Dh)

There you go.

- #5

- 3

- 0

So simple when you can see it..

Thanks for your help, that's been driving me crazy!

- Replies
- 1

- Views
- 965

- Last Post

- Replies
- 2

- Views
- 1K

- Last Post

- Replies
- 1

- Views
- 2K

- Replies
- 3

- Views
- 8K

- Last Post

- Replies
- 2

- Views
- 3K

- Last Post

- Replies
- 30

- Views
- 5K

- Last Post

- Replies
- 6

- Views
- 1K

- Last Post

- Replies
- 8

- Views
- 5K

- Last Post

- Replies
- 1

- Views
- 462

- Last Post

- Replies
- 7

- Views
- 609