Triangle calculation for the resultant velocity

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To calculate the resultant velocity from two components, the hypotenuse of a right triangle is determined using the formula 31.748 m/s, derived from the velocities 30.8 m/s and 7.7 m/s. This hypotenuse represents the combined velocity of the two components. The angle formed with the horizontal is approximately 14 degrees, calculated using the atan2 function. Understanding the resolution of forces in two dimensions is crucial for these calculations. The discussion emphasizes the importance of using trigonometric principles to resolve vector components effectively.
DeanH87
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Homework Statement
Hi, Can someone help with the below calculation. Sample attached
Relevant Equations
See Below
1591845692283.png
Top example- How do I get to 31.7 m/s from 30.8 and 7.7? This is way over my head and need help. Thanks in advance
Dean
 
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##31.748 = \sqrt { 30.8^2 + 7.7^2 }##
It is the length of the hypotenuse of the right triangle formed by the horizontal and vertical numbers.
And the 14 deg is the angle off of horizontal that those two velocities make for the combined velocity.
## 14.03 = (180/\pi) * atan2(7.7, 30.8) ##
 
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Great! Thanks
 
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DeanH87 said:
Homework Statement:: Hi, Can someone help with the below calculation. Sample attached
Relevant Equations:: See Below

View attachment 264461Top example- How do I get to 31.7 m/s from 30.8 and 7.7? This is way over my head and need help. Thanks in advance
Dean
What do you know about resolving forces in 2 dimensions?
 

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