1. The problem statement, all variables and given/known data Two points are selected randomly on a line of length L so as to be on opposite sides of the midpoint of the line. This means that their joint density function is a constant over the region A = (0, L/2) x (L/2, L); normalization to 1 defines the constant. a. Find the probability that the distance between the two points is greater than L/3. b. Find the probability that the three line segments of (0, L) formed by the two points can form a triangle (so as to satisfy the triangle inequality) The attempt at a solution I drew the region on an xy plane, and integrated the constant C twice with respect to each set of limits (L/2 to L, and 0 to L). However, I end up with C = 2/L and don't know what do with this...which means I cant even do the second part of the problem.