Trig Problem: Angular Velocity.

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SUMMARY

The discussion centers on calculating angular velocity and distance traveled on a Ferris wheel with a radius of 25.3 meters that completes two rotations per minute. The average angular speed is determined to be approximately 0.21 radians per second, derived from the formula 4π/60. For the distance traveled over a 5-minute ride, the correct calculation yields 1590 meters, based on the total of 10 rotations, each covering a distance of 2πr. Misinterpretations in the equations were clarified, particularly regarding the factor of 10 versus 20 in the distance calculation.

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Senjai
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Homework Statement



A Ferris Wheel with a radius of 25.3m makes two rotations per minute.

A) Find the average angular speed of the Ferris wheel in radians per second.

B) How far does a rider travel if the ride lasts 5 minutes?

The Attempt at a Solution



A) I got this question after a little bit of trial and error. i stated one rotation was 360 degrees which is equivalent to 2\pi Radians. It rotated twice per minute, so i stated that it rotated 4\pi radians per minute, my final equation to solve for the angular velocity was:

\frac{4\pi}{60} \cong 0.21 radians

B) I can't seem to get this answer. My answer is 794.82, if i multiply it by 2 i get the correct answer so i don't understand where I am missing the 2. the correct answer is 1590 m.

i started with this equation

\frac{10\pi}{2\pi} = \frac{d}{2\pi r}

after some mismatching i canceled out the common term of 2 pi on both sides and got:

d = 10\pi r which yields the aforementioned answer. Does anyone know what I'm missing?

Thanks,

Senjai
 
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One full rotation would cover a distance of 2\pi r meters.

With a rate of two rotations per minute, a total of 10 rotations is made in 5 minutes.

Hence, the total distance traveled is 2\pi r * 10 which yields the required answer.Im not 100% sure where that equation you wrote came from ( <br /> \frac{10\pi}{2\pi} = \frac{d}{2\pi r} <br />), but i suspect that the 10\pi should be 20\pi, the total angle covered?
 
I got that equation from the fact the sector angle is proportional to an increase in sector or arc. But i understand where your coming from. Thanks for all your help!
 

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