Trig problem (Diagram included)

  • Thread starter Thread starter supernova1203
  • Start date Start date
  • Tags Tags
    Trig
Click For Summary

Homework Help Overview

The problem involves determining the height of a building based on the angles of elevation to the top and bottom of a satellite dish situated on the building. The angles provided are 39.1 degrees and 44.7 degrees, with the dish itself being 5 meters high.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of trigonometric laws, particularly the sine and tangent ratios, to solve for the height. There is mention of recalculating based on the correct application of these ratios and questioning the accuracy of labeled sides in the diagram.

Discussion Status

Some participants have offered corrections regarding the calculations and the labeling of angles in the diagram. There appears to be ongoing exploration of the correct approach to using trigonometric functions to find the height, with no clear consensus on the final value yet.

Contextual Notes

Participants note discrepancies in the diagram, such as the incorrect labeling of angles and the lengths of sides, which may affect the calculations. There is also a mention of the challenge in incorporating the height of the dish into the calculations.

supernova1203
Messages
209
Reaction score
0

Homework Statement


A satellite dish that is 5m high sits atop a building, from a point at the base of building, the angles of elevation of the bottom and the top of the satellite dish are 39.1 degrees and 44.7 degrees. Determine the height of the building to one decimal place.


Homework Equations



Sine law: a/SinA = b/SinB=c/SinB

Cosine law: c^2=a^2+b^2-2abCosC

Pythagorean theorem: a^2+b^2= c^2



The Attempt at a Solution



We are originally just given the 5m and the 2 angles 44.3 degrees and 39.1 degrees
rest is included in diagram which i obtained either using one of the 3 laws or the supposition that a triangle has in total a 180 degrees of angles.

triangle = 3 angles which total in 180.
 

Attachments

  • height problem 01.jpg
    height problem 01.jpg
    14.2 KB · Views: 417
Physics news on Phys.org
The side labeled "5.09 m" can't be right. That is the longest side of the top triangle, so it has to be greater than 36.35 m. After you fix that, use the sine ratio for either right triangle to solve for h.
 
Last edited:
eumyang said:
The side labeled "5.09 m" can't be right. That is the longest side of the top triangle, so it has to be greater than 36.35 m. After you fix that, use the sine ratio for either right triangle to solve for h.

your right, first off in my calculations i used tan, instead of sin which would make sense, i re did the calculations and it comes out to be 51.5 m instead of 5.09m.

Also the course teaches us how to use the sine ration, but it ends up being h+5 which is hard for me to solve @_@
 
supernova1203 said:
your right, first off in my calculations i used tan, instead of sin which would make sense, i re did the calculations and it comes out to be 51.5 m instead of 5.09m.

Also the course teaches us how to use the sine ration, but it ends up being h+5 which is hard for me to solve @_@

I'm not getting 51.5m either.

Also, it's not hard using the sine ratio. Using the hypotenuse of the smaller right triangle (which is about 36.42, not 36.35), you don't even need to worry about the h+5:
\sin 39.1^{\circ} = \frac{h}{36.42}

EDIT: Also, θ1 + θ2 in the diagram is incorrectly labeled as 44.3°. It should be 44.7°
 
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
2
Views
1K
  • · Replies 13 ·
Replies
13
Views
4K
Replies
5
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
24K
  • · Replies 9 ·
Replies
9
Views
3K