Trig simplifycation and Intergration

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Homework Help Overview

The discussion revolves around the application of cylindrical shells in integration, specifically for the function y=sin(x^2) over the interval from x=0 to x=sqrt(pi), with rotation around the y-axis.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to simplify the expression x*sin(x^2) for integration and considers substitution as a method. There are questions regarding the necessity of changing the bounds of integration after substitution.

Discussion Status

Participants are exploring the substitution method and discussing the implications of changing integration bounds. Some guidance has been provided regarding the correct bounds after substitution, but there remains some uncertainty from the original poster about this aspect.

Contextual Notes

The discussion includes a focus on the integration process and the need to adjust bounds when changing variables, highlighting potential confusion around this concept.

lemurs
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kay doing Cylidical Shells and what not.

given y=sin(x^2)
from x=0..sqr(pi)
and rottated around the y-axis.

I use the formula for intergration

V=2(pi)x F(x) d(x)

i get when i subsitute

2(pi)x Sin(x^2) d(x)
I know since 2(pi) is constan i pull it through the intergral.
Can I simplify : x Sin(x^2) into something easier for integration.
 
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Substitution.
 
just want to make sure i did it right.. since it's been a while since i did substition.

for my question i woul have
u=x^2

du/dx=2x
du=2x dx
1/2(du) = x dx. which will fit into my orginal equation.
 
That all looks right. Make sure to change the bounds as well.
 
kay lost me there what you mean change the bounds?
 
The integration goes from x=0 to x=sqrt(pi), so from u=0 to u=pi.
 
ok.. don't understnad why i have to change my bounds... but iwill take your word for it.
 
Good, that's the way math should be done. Seriously, what don't you understand? If you want to integrate from x=0 to x=sqrt(pi), and you have set u=x^2, then to integrate over the same region you need to go from u=0^2=0 to u=(sqrt(pi))^2=pi.
 

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