Trigometric Identies Rearrangement

[thomas49th]

Homework Statement

I have the term:

2tan2x + (2x-1)(2sec²2x) = 0

I need to rearrange it into the form

4x + sin4x - 2 = 0

I tried:
\frac{2sin2x}{cos2x} + \frac{2(2x-1)}{cos²2x} = 0

i multiply each side by cos²2x

2.Sin2x.Cos2x + 4x - 2= 0

but now where?

Thanks

 

[Vid]

Look at the sine double angle identity.

 

[thomas49th]

i thought about that but you can't use it... can you?

sin2x = 2sinxcosx

you could do

2(2sinxcosx)cos2x + 4x - 2

or can you do somthing with the 2sin2xCos2x ? it's 2x not x so you can't equate it to sin2x

Not sure :/

Thanks

 

[Vid]

Let u = 2x

2sin(u)cos(u) = sin(2u)

 

[thomas49th]

but to equal sin4x doesn't it need to be 4sinxcosx not 2sin2xcos2x?

Thanks

 

[Vid]

Not at all.
Obviously 2sin(u)cos(u) = sin(2u) is true since the variable inside the formula doesn't matter. Now, replace u with 2x.
2sin(2x)cos(2x) = sin(2*(2x)) = sin(4x).
There's no need for another 2 out in front.

 

[thomas49th]

and that's ture for all double angle formulas
and similar for the half angle formulas?

Cheerz :)