Trigonometric identities hard question

[DJ-Smiles]

Homework Statement

Simplify the following:
sin(b)/cos(b) + cos(b)/sin(b)

Homework Equations

Trigonometric identities

The Attempt at a Solution

Ok so i have no clue how to do this,I keep trying but can't seem to get the right answer, I have tried to do this:

sin(b)/cos(b) + cos(b)/sin(b)
=tan(b)+ 1/tan(b)
=tan(b)+cot(b)

I know this isn't right and I am encountering these types of questions quite often now, so I really need help. Please help me.

 

[SammyS]

Homework Statement

Simplify the following:
sin(b)/cos(b) + cos(b)/sin(b)

Homework Equations

Trigonometric identities

The Attempt at a Solution

Ok so i have no clue how to do this,I keep trying but can't seem to get the right answer, I have tried to do this:

sin(b)/cos(b) + cos(b)/sin(b)
=tan(b)+ 1/tan(b)
=tan(b)+cot(b)

I know this isn't right and I am encountering these types of questions quite often now, so I really need help. Please help me.

Well, it is true that sin(b)/cos(b) + cos(b)/sin(b) = tan(b) + cot(b) , but you probably need to come up with something more surprising.


Use a common denominator to combine sin(b)/cos(b) + cos(b)/sin(b) into one fraction. Yo may be surprised by what the numerator simplifies to.

 

[DJ-Smiles]

yeah I know it's just that the answer is 1/cos(b)sin(b). How would I get to this?

 

[SammyS]

yeah I know it's just that the answer is 1/cos(b)sin(b). How would I get to this?

As I said before,

se a common denominator to combine sin(b)/cos(b) + cos(b)/sin(b) into one fraction.​