The "triplet paradox" that comes up in my Googling and search results involve one triplet that stays at rest and the other two venture out and back again, but in opposite directions. Essentially two "twin paradoxes" occurring together.(adsbygoogle = window.adsbygoogle || []).push({});

But what about a scenario in which triplets A and B are together and triplet C is waiting at some far-off location many light years away [maybe not triplets, per se, but three individuals born at the same time in the same reference frame.] A and C remain at rest. Let's say B departs A at 0.8c heading toward C. Since A and C remain in the same reference frame, albeit many light years apart, obviously they share simultaneity planes and age "together at the same rate," right? But how does B's age compare to A and C when he gets to C's location?

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I'm not sure what I'm missing, but I can't seem to wrap my head around it. Maybe I just need some very-detailed Minkowski diagrams (I really don't know.) Thanks. :-)

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# "Triplet Paradox" involving a single one-way trip

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