Trouble solving this Determinant

  • Thread starter shiri
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  • #1
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I'm having trouble solving this question:

If det

| a b c |
| p q r | = 2,
| u v w |

find det (3B^-1) where B =

| 2u 3u-a a-p |
| 2v 3v-b b-q |
| 2w 3w-c c-r |

Is it possible to transpose B?

So far what I got is 4; however, the instructor told me that the answer is |B| = 27/4
 

Answers and Replies

  • #2
LCKurtz
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Remember there is a difference between a determinant and a matrix. I'm guessing you are given a matrix

[tex]B =\left [
\begin{array}{ccc}
2u&3u-a&a-p\\
2v&3v-b&b-q\\
2w&3w-c&c-r

\end{array}
\right ][/tex]

and what you have written is its determinant. Remember when you multiply a matrix by 3 it multiplies every element in the matrix. So for an n by n matrix A, if you multiply it by 3 and take its determinant, a 3 comes out of every column so

det(3A) = 3ndet(A)

That plus the fact that det(A-1) = 1 / det(A)
should help you out.
 

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