# Trouble with deducing the contradiction

1. Jul 6, 2012

### tt2348

Let x,y,z be integers satisfying a specific condition, which boils down to
$5|(x+y-z)$ and $2*5^{4}k=(x+y)(z-y)(z-x)((x+y)^2+(z-y)^2+(z-x)^2)$
or equivalently $5^{4}k=(x+y)(z-y)(z-x)((x+y-z)^2-xy+xz+yz)$
I want to show that GCD(x,y,z)≠1, starting with the assumption 5 dividing (x+y), (z-y), or (z-x) results in x,y or z being divisible by 5. then it's easy to show that 5 divides another term, implying 5 divides all three.
I run into trouble assuming 5 divides the latter part, $2((x+y)^2+(z-y)^2+(z-x)^2)=((x+y-z)^2-xy+xz+yz)$ and showing the contradiction from that point.
Any hints?

2. Jul 8, 2012

### haruspex

Suppose 5 | a2+b2+c2. Each term individually must be 0, 1 or 4 mod 5. The only ways for three such to add to 0 mod 5 involve at least one of them being 0 mod 5, no?