Trouble with Initial Value Condition Questions

In summary, the conversation discusses a question on finding the general solution of an initial value condition problem involving a function z(x,y) and an initial condition z=x on the line y=1. The solution involves replacing z(x,y) with the condition to get x=2x+g(x), finding g(x)=-x, and using functional notation to determine that g(xy)=-xy. The general solution is then given as z(x,y)=2x-xy.
  • #1
porroadventum
34
0
I have been looking at an example of a initial value condition problem in my notes and don't really understand where the solution came from. Here is the question:

Let z(x,y)= 2x+ g(xy) and add the initial value conditon, z= x on the line y=1. Find the general solution of the initial value problem.


1. Replace z(x,y)=2x+g(xy) wih the condition to get x= 2x+g(x) for all x, so that g(x)= -x

I understand everything so far but then the next step says "hence z(x,y)= 2x-xy is the general solution." Where does the -xy come from?

Any help or advice would be much appreciated! Thank you
 
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  • #2
Can you find another relation that would fit the conditions?
 
  • #3
It's just a matter of the "functional notation" you have been using for years:

If g(x)= -x then g(u)= -u, g(a)= -a, g(v)= -v, etc.

In eactly the same way, g(xy)= -xy.
 
  • #4
OK I understand now, thank you
 
  • #5


I understand that initial value condition questions can be challenging to grasp at first. It is important to break down the problem step by step in order to fully understand the solution. In this case, it seems that the confusion lies in the last step where the solution is given as z(x,y)= 2x-xy.

To understand where the -xy comes from, let's go back to the initial equation z(x,y)= 2x+g(xy). We have already determined that g(x)=-x, so we can substitute that into the equation to get z(x,y)= 2x-x(xy). From here, we can factor out an x to get z(x,y)= x(2-y). This is the general solution, but we can also express it as z(x,y)= 2x-xy by distributing the negative sign.

It is important to remember that in mathematics, we can express the same solution in different ways. In this case, both z(x,y)= x(2-y) and z(x,y)= 2x-xy are equivalent and valid solutions to the initial value problem. I hope this explanation helps clarify the solution for you. If you have any further questions, please don't hesitate to ask. Remember, as a scientist, it is important to continue asking questions and seeking understanding in order to further our knowledge and progress in our field.
 

1. What is an initial value condition?

An initial value condition is a mathematical concept that refers to the value of a function (or its derivative) at a specific point in the domain of the function. It is also known as an initial condition or starting condition.

2. Why are initial value condition questions important in science?

Initial value condition questions are important in science because they allow us to predict the behavior of a system over time. By specifying the initial value of a function, we can determine its value at any given point in time, which is crucial for understanding and modeling natural phenomena.

3. How do initial value condition questions differ from boundary value condition questions?

Boundary value conditions are specified at the boundaries of a function's domain, while initial value conditions are specified at a specific point within the domain. Additionally, initial value conditions are used to predict the behavior of a system over time, while boundary value conditions are used to determine the behavior of a system at specific points in its domain.

4. Can initial value condition questions be solved analytically?

In some cases, initial value condition questions can be solved analytically using mathematical techniques such as integration, differentiation, and substitution. However, in more complex systems, numerical methods may be needed to solve initial value condition questions.

5. What are some real-world applications of initial value condition questions?

Initial value condition questions have a wide range of applications in various fields of science, such as physics, chemistry, biology, and economics. Some examples include predicting the population growth of a species, modeling the spread of a disease, and forecasting stock market trends.

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