Trouble with the unit normal vector for stokes theorem

  • Thread starter hivesaeed4
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  • #1
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Main Question or Discussion Point

We're given x^2+2*y^2=1.
so x^2=1-2y^2

now using distance formula
d^2=x^2+y^2
since x^2=1-2y^2, substituting it in the distance formula we get:
d^2=1-2y^2+y^2=1-y^2;
differentiating and then setting the eq to 0 we get;
0=-4y
or y=0. now x^2=1-2y^2=1
so x=+-1
so point having min distance form origin is (+-1,0)

using the distance formula now
d^2=x^2+y^2
d=sqrt(1+0)=1
 

Answers and Replies

  • #2
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Sorry. Wrong post. I intended to preview it but posted it by mistake.
 

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