Troubleshooting a Velocity vs. Time Graph: Position at t=10

Click For Summary

Homework Help Overview

The discussion revolves around interpreting a velocity vs. time graph to determine the position of an object at a specific time, t=10. The graph features segments with varying slopes, and participants are attempting to calculate the area under the curve to find the total displacement.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants describe their attempts to calculate the area under the graph using integration and discuss the significance of slope values. Questions arise regarding the accuracy of calculations and the potential for errors in the problem setup.

Discussion Status

Some participants express uncertainty about the correctness of their calculations and the problem's answer, suggesting that there may be an issue with the electronic system. Others confirm their results align with previous attempts, indicating a lack of consensus on the final answer.

Contextual Notes

There is mention of significant figures being a potential factor in the problem's evaluation. Participants also note the possibility of errors in the electronic answer key, which may affect their conclusions.

Psyguy22
Messages
62
Reaction score
0
We are given a velocity vs. time graph. It starts at 15 m/s at t=0 and goes to -10m/s at t=4
then it goes from -10m/s at t=4 to 15m/s at t=10 and we are told to find the postion after t=10

I first found the slope of the first segment which was -6.25. so I did ∫-6.25t+15 dt from 0 to 4 and got 10m
I found the second slope, 4.16..., and did ∫4.16...t-10 dt from 0-6 (because I moved it to the orgin so it made sense) and got 15m. So I added the two segments to get 25m. But the site keeps saying that's the wrong answer. What am I doing wrong?
 
Physics news on Phys.org
Does the sight care about significant figures? Hard to believe ∫4.16t-10 dt comes out to exactly 15m.
 
It comes to 15 when you put 25/6 which is 4.16 repeating. But yes the site does care about significant figures.
 
oh, I didn't do the math myself I just took it as 4.16 flat. Well I did the math myself as well as taking the area under the curve of the graph and got the same answer as you both ways. Honestly at this point I would say they possibly put in a wrong answer for the problem since it's electronic. I know that's happened to people I know before so you might as well ask.
 
ok thank you for your help!
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
25
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
10
Views
3K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
9K