Twin paradox not including accelerations, it is wrong where?

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    Paradox Twin paradox
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SUMMARY

The forum discussion centers on the twin paradox, specifically challenging the necessity of acceleration in explaining the age difference between twins. The user Luis proposes a scenario using Polaroid photos to illustrate his point that even without acceleration, the traveling twin's photo would show less degradation than the non-traveling twin's photo. Respondents clarify that the key factor is the change in inertial frames rather than acceleration, emphasizing that different paths through spacetime lead to different aging outcomes. The discussion highlights common misconceptions regarding the role of acceleration and the relativity of simultaneity in the twin paradox.

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  • #61
Thanks for your clarification.
 
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  • #62
I think that gravity is more appropriate term in explanation of twin-paradox than acceleration. An egocentric traveler twin who believes he never move and keep still, would interpret that time dilation is due to a sudden appearance of gravitation field in all over the space including the Earth though he cannot explain why it appears.
 
  • #63
sweet springs said:
I think that gravity is more appropriate term in explanation of twin-paradox than acceleration.

The best explanation, as has already been said in this thread, is the different lengths of the two paths through spacetime.

sweet springs said:
though he cannot explain why it appears

Which is a good reason not to say that gravity is a "more appropriate" explanation.
 
  • #64
Yea, the best explanation, right.
I would like to just add transfer of inertial frames is more appropriate (not the best) word than acceleration in twin-paradox explanation. When a massive body keep still during its changing the frame of reference, acceleration or force always work on it and vice versa. These are two equivalent sayings. But for information transfer as in post #7 the former applies, the latter does not.
 
  • #65
sweet springs said:
transfer of inertial frames is more appropriate (not the best) word than acceleration

"Transfer of inertial frames" is vague. Also it's not physical--"inertial frames" is a term for an abstract model made by humans, not a physical happening. Also it's unnecessary: you can just say "path through spacetime" and not have to worry about frames at all.

sweet springs said:
When a massive body keep still during its changing the frame of reference

I think I understand what you're trying to say, but this is not a good way to say it. A better way would be to say that if an object has nonzero proper acceleration, any frame in which it is at rest must be a non-inertial frame; it can't be at rest in an inertial frame for more than an instant. That puts the physical observable (proper acceleration) before the abstract model (a frame).

sweet springs said:
for information transfer as in post #7 the former applies, the latter does not.

See above.
 
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  • #66
The twin paradox absolutely does not need any mention of acceleration. And it is very easy to understand the asymmetry to boot. The traveling twin sees the distance to the destination to be length contracted, the earth-bound twin does not.
 
  • #67
f todd baker said:
The twin paradox absolutely does not need any mention of acceleration. And it is very easy to understand the asymmetry to boot. The traveling twin sees the distance to the destination to be length contracted, the earth-bound twin does not.
You are right that the acceleration is not required to explain the twin paradox, but mistaken about the role of length contraction. If we use coordinates in which the traveling twin is at rest on the outbound leg, the earthbound twin will find that leg is shorter than the traveling twin; and likewise for the return leg when we use coordinates in which the traveller is at rest on the return leg.

It is not possible to link too often to the twin paradox FAQ: http://math.ucr.edu/home/baez/physics/Relativity/SR/TwinParadox/twin_paradox.html
 
  • #68
Nugatory said:
You are right that the acceleration is not required to explain the twin paradox, but mistaken about the role of length contraction. If we use coordinates in which the traveling twin is at rest on the outbound leg, the earthbound twin will find that leg is shorter than the traveling twin; and likewise for the return leg when we use coordinates in which the traveller is at rest on the return leg.

It is not possible to link too often to the twin paradox FAQ: http://math.ucr.edu/home/baez/physics/Relativity/SR/TwinParadox/twin_paradox.html
If the traveler is taken to be at rest, there is no length contraction because the earth-bound twin and the destination are in the same frame.
 
  • #69
f todd baker said:
If the traveler is taken to be at rest, there is no length contraction because the earth-bound twin and the destination are in the same frame.
There is length contraction because the frame in which the Earth bound twin and the destination are at rest is one you have chosen to consider as being in motion.
 
  • #70
jbriggs444 said:
There is length contraction because the frame in which the Earth bound twin and the destination are at rest is one you have chosen to consider as being in motion.
Sorry, I am not getting your point. Regardless of which frame you choose to be at rest, the traveling twin sees the distance from Earth to destination to be contracted and the Earth bound twin does not see that distance contracted. What we have here is a failure to communicate!
 
  • #71
f todd baker said:
the traveling twin sees the distance from Earth to destination to be contracted
Ummm, is that not "length contraction"?
 
  • #72
f todd baker said:
Regardless of which frame you choose to be at rest, the traveling twin sees the distance from Earth to destination to be contracted and the Earth bound twin does not see that distance contracted.

When you choose to observe things from the traveling twin's perspective, you choose the frame in which he is at rest.

Likewise when you choose to observe things from the staying twin's perspective, you choose the frame in which he is at rest.

Thus you cannot claim to to be making observations without regard to which frame you've chosen.
 
  • #73
In the Hitchcock version, during the outgoing trip, it is suspensefully anybody's guess which twin will turn out to be the "outgoing" one, and whose frame-dependent length contraction will appear to be relevant at the end of the scenario.
 
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