Two blocks on a double incline plane

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SUMMARY

The discussion focuses on solving a physics problem involving two blocks on a double incline plane, utilizing Newton's second law (F=MA) to derive the equations of motion. The user correctly identifies the forces acting on each block, including the normal force, gravitational force, and tension in the string. The approach involves balancing forces perpendicular to the incline and calculating net acceleration along the plane, specifically using the equation T - M2gSin(32) = M2a for block M2. This method effectively simplifies the problem by avoiding separate components for the X and Y axes.

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Homework Statement


See attachment


Homework Equations


F=MA
T=MA?



The Attempt at a Solution


M1:
N1=M1gSin(32)
T=M1gCos(32)

Now does this work?:
T=MA
M1A=M1gCos(32)

and that would give me the acceleration for the X-axis and i could do the same for the Y-axis and get the magnitude?
 

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Let the block M2 move down the plane and 'a' be its acceleration along the plane.
The forces acting on it are-
1)the normal force by the plane (perpendicular to the plane)
2)its weight vertically downwards
3)tension in the string

Forces perpendicular to the plane balance each other.
Forces along the plane are responsible for its acceleration.
No need to calculate separate components of acceleration for x and y axes respectively.
Just calculate its net acceleration along the plane.
 
Thank you very much!
Doing that ill set up T-Mgsin32=ma and ill do the same for m2 and solve for acceleration
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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