Two blocks on a double incline plane

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XwakeriderX
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Homework Statement


See attachment


Homework Equations


F=MA
T=MA?



The Attempt at a Solution


M1:
N1=M1gSin(32)
T=M1gCos(32)

Now does this work?:
T=MA
M1A=M1gCos(32)

and that would give me the acceleration for the X-axis and i could do the same for the Y-axis and get the magnitude?
 
Attachments
  • Physics problem diagram: two blocks on a frictionless double inclined plane joined by a string over a pulley at the peak. Left block M1 = 3.00 kg on a 32.0 degree incline; right block M2 = 4.00 kg on a 47.0 degree incline. Problem text above asks for acceleration and string tension.
    2 blocks on incline.jpg
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Let the block M2 move down the plane and 'a' be its acceleration along the plane.
The forces acting on it are-
1)the normal force by the plane (perpendicular to the plane)
2)its weight vertically downwards
3)tension in the string

Forces perpendicular to the plane balance each other.
Forces along the plane are responsible for its acceleration.
No need to calculate separate components of acceleration for x and y axes respectively.
Just calculate its net acceleration along the plane.
 
Thank you very much!
Doing that ill set up T-Mgsin32=ma and ill do the same for m2 and solve for acceleration