2 really tricky ones for me on this homework assignment. I think I got the other one settled (Thanks to help here) -- now I just need to finish this last one. 1. The problem statement, all variables and given/known data Two blocks sit on this frictionless table, but there is friction between the blocks. Static = .589 Kinetic = .332 A = 100 kg B = 10 kg What minimum force F must be exerted on A in order for B not to fall? 2. Relevant equations F=m•a R - the static resistive force ---> fs*F=R 3. The attempt at a solution Attempt 1: Since B isn't moving, I'll use the static friction force. I know that the force that A applies on B, times the static force, will be my upward force -- which I need to counter the downward force of gravity. Since B is 10kg, I need 98 kg of up force. 98/589 = 166.4 N So Force to move block A = 980 N Force to move block B = 98 N 980+98+166.4=1244 N The only problem is I am given a range for the answer, and I need to be between 1700 and 2200, so I know that answer is wrong. Once I find the force, then I'm supposed to find the overall acceleration...I think that should be easy, once I know the force.