1. The problem statement, all variables and given/known data Consider the setup shown below. The blocks have masses 8.2 kg and 25 kg. The pulley has mass 5.9 kg, and is a uniform disc with radius 0.25 m. Assume the pulley to be fric- tionless, but the coefficient of friction between the block and the surface is 0.28.What is the acceleration of the blocks? Assume the 25 kg mass is descending with acceleration a. The moment of inertia of the disk is 1/2MR2 and the acceleration of gravity is 9.8 m/s2 . Answer in units of m/s2. 2. Relevant equations Torque= (radius)(force)sin(angle between them)= (inerta)*(alpha)or (inertia)*a/r sumF=ma friction= (mew)*(normal force) 3. The attempt at a solution mo= mass of pulley I think this problem just has too much algebra =.= sumF1x= m1gsin(theta)+Friction-T1=m1a SumF2y=T2-m2g=m2a sumT= 1/2(mo)ra= rt1-rt2 ( I don't know which one should go first or why) solving the t and plugging it into torque I receive: a= g( (1+(mew))m1sin(theta)-m2) ----------------------------- (1/2mo+m1+m2) I have a practice problem I can use to verify if i set this problem up but I keep getting like .05 off -.- Any help would be appreciated!