Two-Dimensional Motion and Vectors

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The discussion focuses on calculating the total displacement along U.S. Highway 212, which extends 55 km at a 37-degree angle north of east and then 66 km due east. The calculations involve breaking down the two segments into their x and y components using trigonometric functions. The final displacement is determined using the Pythagorean theorem, resulting in a total displacement of 115 km. The problem emphasizes the importance of vector addition in two-dimensional motion. Understanding these calculations is crucial for solving similar physics problems.
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Homework Statement


U.S. Highway 212 extends 55km at 37 degrees north of east between Newell and Mud Butte, south Dakota. It then continues for 66 km nearly due east from Mud Butte to Faith, South Dakota. If you drive alongthis part of U.S. Highway 212, what will your total displacement be?

X1=55(cos37) Y1=55(sin37)
X2=66(cos0) Y2=66(sin0)

Homework Equations


d^2=X^2+Y^2


The Attempt at a Solution


D=115km
 
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eaglesfan94 said:

Homework Statement


U.S. Highway 212 extends 55km at 37 degrees north of east between Newell and Mud Butte, south Dakota. It then continues for 66 km nearly due east from Mud Butte to Faith, South Dakota. If you drive alongthis part of U.S. Highway 212, what will your total displacement be?

X1=55(cos37) Y1=55(sin37)
X2=66(cos0) Y2=66(sin0)

Homework Equations


d^2=X^2+Y^2


The Attempt at a Solution


D=115km
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