Two infinite charged lines -- find the locations where E=0

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SUMMARY

The discussion focuses on determining the locations where the electric field (E) is zero between two infinite charged lines, one with a charge density of +1λ and the other with -2λ. The relevant equation for the electric field due to an infinite line charge is E = (1/(2πε₀))(λ/r). The solution involves setting up the equation λ1/r + λ2/(d-r) = 0, substituting λ2 = -2λ1, and solving for the distance r in terms of d. This approach leads to identifying the specific points where the electric field cancels out.

PREREQUISITES
  • Understanding of electric fields generated by line charges
  • Familiarity with the concept of charge density (λ)
  • Knowledge of Coulomb's law and its application to electric fields
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the derivation of the electric field from an infinite line charge using E = (1/(2πε₀))(λ/r)
  • Explore the relationship between linear charge density (λ) and surface charge density (σ)
  • Learn about superposition principles in electric fields
  • Investigate the effects of varying charge densities on electric field distributions
USEFUL FOR

Physics students, electrical engineers, and anyone studying electrostatics or electric field theory will benefit from this discussion.

Grifter
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Homework Statement



A very long (infinite), straight line of charge runs parallel to another very long (infinite) straight line of charge. Both lines are uniformly charged, one with +1*(lambda) and the other with -2*(lambda). The distance between them is d. Find (if any) the location(s) where the electric field is zero.

Homework Equations



[infinite wire] E = 1/(2(pi)(epsilon naught)) * (lambda)/r
[2 wires] E = (sigma1)(sigma2) / 2(epsilon naught)
sigma=area charge
lambda=line charge
epsilon naught=8.854e-12 C^2/N*m^2

The Attempt at a Solution



I drew a picture with the positively charged line with E-lines flowing away and the negatively charged line with E-lines flowing in. Between the E-lines flow from positive to negative. Not sure about the relationship between lambda and sigma or how to use an equation to find E=0 with variable charges.
 
Last edited:
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From a distance r from a wire of charge lenght-density λ (Coloumb per meter) the electric field strenght is proportional to λ/r

You want to solve the equation λ1/r + λ2/(d-r) = 0
Just use that λ2 = -2λ1 and solve for r in terms of d
 

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