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Two parallel springs, frequency change?

  1. Apr 4, 2013 #1
    Ok, you guys! Please note that this is NOT a homework question but merely something that's been bothering me for a while.

    We have a vertical spring with a hanging mass M. We pull the mass down and let it go, thus creating a harmonic oscillator with the frequency f.

    What happens with the frequency when we attach our weight to two parellel springs of the same type as described above?

    I've been thinking about this one for a while now so any help is more than welcome.

    Many thanks,
    Stephen
     
  2. jcsd
  3. Apr 4, 2013 #2
    Nvm, I think I finally got it. The answer is 2^(1/2)*old frequency. :)
     
  4. Apr 5, 2013 #3

    sophiecentaur

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    Yes, the spring constant will double so the f will increase by √2.
     
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