(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

y^{''}+[tex]\lambda[/tex]y=0

y^{'}(0)=0

y^{'}(pi)=0

2. Relevant equations

3. The attempt at a solution

What's puzzling me is the case when we check if the eigenvalue is zero.

y^{''}=0

y^{'}=C_{1}

y=C_{1}x+C_{2}

Now when I check the first boundary value I get C1=0

now How do I check the second one ? with the pi...

It doesn't make sense plugging into the first derivative again because I have no x value (only a constant).

The answers show this:

lambda=0 is an eigenvalue and the general solution is y_{0}(x)=1

How did they get this ?

Thanks.

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# Homework Help: Two-Point Boundary Value Problem

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