- #1

Bobbo Snap

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## Homework Statement

Two particles, each of mass

*m*and having charge

*q*, are suspended by strings of length

*l*from a common point. Find the angle

*θ*which each string makes with the vertical.

## Homework Equations

[tex] F_e = k \frac{q^2}{r^2}, \quad F_G = -mg, \quad F_T = \text{tension on string}, \quad r = 2l\sin{\theta}[/tex]

## The Attempt at a Solution

Since [itex]F_{net} = \vec{0}[/itex], I set [itex]F_e = -F_T \sin{\theta}[/itex] and [itex]F_G = - F_T \cos{\theta}[/itex]. After some manipulation, I get [tex] \tan{\theta} = k \frac{q^2}{r^2 m g}.[/tex]

After I substitute [itex]r = 2l \sin{\theta}[/itex], I can't figure out how to solve for theta. I feel like I'm missing something simple. Any suggestions?

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