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Fredrik

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*exactly*are the axioms of non-relativistic QM of one spin-0 particle? The mathematical model we're working with is the Hilbert space [itex]L^2(\mathbb R^3)[/itex] (at least in

*one*formulation of the theory). But then what? Do we postulate that observables are represented by self-adjoint operators? Do we say that a measurement of an operator [itex]A[/itex] on a system prepared in state [itex]|\psi\rangle[/itex] yields result a

_{n}and leaves the system in the eigenstate [itex]|n\rangle[/itex] with probability [itex]|\langle n|\psi\rangle|^2[/itex]? Then how do we handle e.g. the position and momentum operators, which don't have eigenvectors?

Can the problem of unbounded operators be solved without the concept of a "rigged Hilbert space"? Is it easy to solve when we

*do*use a rigged Hilbert space? What

*is*a rigged Hilbert space anyway?

I think I brought this up a few years ago, but apparently I wasn't able to understand it even after discussing it. I think I will this time, because of what I've learned since then. Don't hold back on technical details. I want a complete answer, or the pieces that will help me figure it out for myself.