Uncertainty Principle and Operator Algebra

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The discussion revolves around deriving the Heisenberg uncertainty principle using operator algebra, specifically focusing on position and momentum observables. Participants are exploring the implications of the commutation relation [r,q]=iq and its effects on the uncertainties of measurements. The conversation includes questions about the self-adjoint nature of operators and the normalization of state vectors. There is also a focus on minimizing an equation involving expectation values to demonstrate the relationship between uncertainties in position and momentum. The thread highlights challenges in understanding the mathematical steps required to reach the conclusion of the uncertainty principle.
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Homework Statement

The Heisenberg uncertainty principle can be derived by operator algebra , as follows. Consider a one-dimensional system, with position and momentum observables x and p. The goal is to find the minimum possible uncertainties in the predicted values of the position and momentum in any state |\varphi> of the system. We need the following preliminaries.

Homework Equations


The Attempt at a Solution



a) Suppose the self-adjoint observables q and r satisfy the commutation relation

[r,q]=iq, where c is a constant(not an operator). Show c is real.

should I take the self-adjoint of [r,q], i.e.[r,q]^{\dagger} ?

b) Let the system have the normalized state vector |\varphi> and define the ket vector

|\phi>=(\alpha*r+iq)|\varphi> where \alpha is a real constant(again, a number , not an operator). used equations <\phi|\phi> >=0 and [r,q]=ic to show that

\alpha^2<r^2>-\alpha*c+<q^2>>=0, where <r^2>=<\varphi|r^2|\varphi> and q^2

Should I begin by finding <\phi|\phi>?

Since, |\phi>=(\alpha*r+iq)|\varphi> would that mean <\phi|=<|\varphi(\alpha*r-iq)

c) By seeking the value of \alpha that minimizes the left side of the equation \alpha^2<r^2>-\alpha*c+<q^2>>=0, show

<r^2><q^2>=c^2/4

should I multiply the expectation value <r^2> to the equation \alpha^2<r^2> -\alpha*c+<q^2>>=0
 
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