Unclear differential equation from a thermodynamics textbook

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SUMMARY

The discussion centers on the application of the product rule in calculus to derive the expression from the thermodynamics textbook: 𝛿𝐴 = 𝑇𝑑𝑆 βˆ’ π‘‘π‘ˆ = βˆ’π‘‘(π‘ˆ βˆ’ 𝑇𝑆) βˆ’ 𝑆𝑑𝑇. Specifically, the bolded area is derived by applying the product rule to the term 𝑇𝑆, resulting in the differential d(TS) = TdS + SdT. This application clarifies the transition from TdS to the subsequent terms in the equation, emphasizing the importance of understanding derivatives in thermodynamic contexts.

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NODARman
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In the thermodynamics textbook there is written: 𝛿𝐴 = 𝑇𝑑𝑆 βˆ’ π‘‘π‘ˆ = 𝑑(𝑇𝑆) βˆ’ 𝑆𝑑𝑇 βˆ’ π‘‘π‘ˆ = βˆ’π‘‘(π‘ˆ βˆ’ 𝑇𝑆) βˆ’ 𝑆𝑑𝑇 = βˆ’π‘‘πΉ βˆ’ 𝑆𝑑𝑇
How did we get the bolded area from TdS? Is that property of derivative, integral, or something else :/
 
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Product rule
 
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Sorry for being so terse. I was posting from my phone.

Apply the product rule to ##TS##. ##d(TS) = ?##.
 
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