Understanding and Solving DiffEq: x' = 2*x^(1/2)

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SUMMARY

The differential equation x' = 2*x^(1/2) is separable and can be solved by rewriting it as dx/(2*x^(1/2)) = dt. Integrating both sides yields the general solution, which includes a constant of integration. While the solution x = t^2 satisfies the equation, the complete solution provided by Wolfram is 1/4 (4t^2 + 4tC + C^2), which accounts for the integration constant. Understanding the integration process is crucial for deriving the complete solution.

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  • Understanding of differential equations
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  • Knowledge of separable differential equations
  • Experience with mathematical software like Wolfram Alpha
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  • Study the method of separation of variables in differential equations
  • Learn about integrating factors for solving first-order DEs
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Homework Statement



I have the differential equation:

x' = 2*x1/2

The Attempt at a Solution



I can see easily that the solution x = t2 satisfies the equation, however wolfram tells me the solution is:

1/4 (4 t2 + 4 t C + C2)

which also satisfies the solution... I'm wondering how do I solve this differential equation in order to get the solution Mathematic got?
 
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pergradus said:

Homework Statement



I have the differential equation:

x' = 2*x1/2

The Attempt at a Solution



I can see easily that the solution x = t2 satisfies the equation, however wolfram tells me the solution is:

1/4 (4 t2 + 4 t C + C2)

which also satisfies the solution... I'm wondering how do I solve this differential equation in order to get the solution Mathematic got?
This DE is separable. Write it as
dx/dt = 2x1/2
=> dx/(2x1/2) = dt

Now integrate both sides. Don't forget the constant of integration.
 

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