Understanding Angular Momentum and Torque in Rotating Objects

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SUMMARY

The discussion focuses on the behavior of a uniform rod rotating about its longitudinal axis when a perpendicular force is applied. The applied force induces a torque that alters the angular momentum vector, resulting in a new angular momentum vector L2, which is the vector sum of the initial angular momentum L1 and the change in angular momentum ΔL. This interaction causes the rod to precess rather than abruptly change direction, indicating that the torque does not solely cause vertical movement but also initiates rotation about a secondary axis.

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  • Understanding of angular momentum and torque concepts
  • Familiarity with vector addition in physics
  • Knowledge of rotational dynamics
  • Basic principles of forces and motion
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  • Study the principles of torque in rotational motion
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  • Explore the effects of impulsive forces on angular momentum
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Physics students, educators, and engineers interested in the dynamics of rotating objects and the effects of applied forces on angular momentum.

SprucerMoose
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Hey guys,

If I have a uniform rod rotating about its longitudinal axis of symmetry in space it will have an angular momentum vector that is colinear to this axis. If I now apply a force directly perpendicular to this (as shown in attachment) it will induce a torque that is perpendicular to the angular momentum vector. The centre of mass of the object must accelerate in the direction of the applied force and the torque will cause a change in angular momentum.

My question is will this torque just cause this rod to kick up or down, i.e. the angular momentum vector follows the direction of the torque vector and/or will the rod also attempt to rotate about axis 2 in the diagram? If it does rotate about axis 2, where does the torque come from to change the perpendicular angular momentum vector.

torque question.jpg
 
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I'm assuming you mean the applied force F is impulsive. Let the initial angular momentum be L1, pointing to the right. The torque resulting from F will cause a change in angular momentum, adding a vertical component ΔL. The new total angular momentum will be the vector sum L2 = L1 + ΔL. As a result the rod is no longer rotating about its axis of symmetry. At the instant the force was applied, the rod was pointing directly to the right. It will not suddenly change direction, but rather wobble (precess) about the direction of L2.
 

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