Understanding Arc Length and Line Integrals for Surface Area Calculation

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SUMMARY

The discussion focuses on the calculation of surface area using line integrals and the definition of arc length. The formula for arc length is clarified as L = lim_{n→∞}∑(P_{i-1}*P_{i}), where the arc length is approximated by dividing a curve into n pieces and taking the limit. The correct expression for arc length in three dimensions is given by the integral ∫_{t_0}^{t_1}√((dx/dt)² + (dy/dt)² + (dz/dt)²) dt. Participants emphasize the distinction between arc length and area, asserting that multiplying a curve function by arc length does not yield an area.

PREREQUISITES
  • Understanding of calculus concepts, particularly line integrals and arc length.
  • Familiarity with parametric equations in three dimensions.
  • Knowledge of integration techniques, specifically in the context of calculus.
  • Basic understanding of vector functions and their applications.
NEXT STEPS
  • Study the derivation and applications of line integrals in fluid dynamics.
  • Learn about the properties of parametric curves and their arc lengths.
  • Explore the relationship between arc length and surface area calculations.
  • Review advanced calculus topics, including multivariable integration techniques.
USEFUL FOR

Students and professionals in mathematics, engineering, and physics, particularly those involved in fluid dynamics and surface area calculations using calculus.

rppearso
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Hello, I am trying to solve for the surface area of a odd surface for a fire relief PSV and needed to do a line integral but I was reading into my calculus book and going back to the definition of arc length I am confused:

L = lim[tex]_{n\rightarrow\infty}\sum (P_{i-1}*P_{i})[/tex]

Multiplication should give you an area like when you multipy the function of a curve C by the length just like an integral. This is a fundamental definition so I can not go back any farther maybe I am just missing something logically in my own mind. Understanding line integration is also fundamental to fluid dynamics and E&M which are both of great interest to me.
 
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rppearso said:
Hello, I am trying to solve for the surface area of a odd surface for a fire relief PSV and needed to do a line integral but I was reading into my calculus book and going back to the definition of arc length I am confused:

L = lim[tex]_{n\rightarrow\infty}\sum (P_{i-1}*P_{i})[/tex]
First what are Pi and Pi-1? Without knowing that we can't make any sense out of that formula. Also, where did you get that formula? I don't recognize it.
If you divide a curve into n pieces, then the arclength is the sum of the length of anyone piece which, for large n, can be approximated by the straight line between the endpoints:
sum [itex]\sqrt{((x_i- x_{i-1})^2+ (y_i- y_{i-1})^2+ (z_i- z_{i-1})^2}[/itex] and the actual arc length is the limit as n goes to infinity.

Multiplication should give you an area like when you multipy the function of a curve C by the length just like an integral.
I have no idea what you mean by this. By "the function of a curve" I presume you mean something like the f(x) in y= f(x) or the vector function [itex]\vec{r}(t)= f(t)\vec{i}+ g(t)\vec{j}+ h(t)\vec{k}[/itex]. But the product of either of those by a number (the arclength) is not a number (the area). And what area are you talking about? In general, an arc does not have any "area" associated with it.

This is a fundamental definition so I can not go back any farther maybe I am just missing something logically in my own mind. Understanding line integration is also fundamental to fluid dynamics and E&M which are both of great interest to me.
In general, if a curve in 3 dimensions is given by (x(t),y(t),z(t)), that is, as parametric functions of t, then the arclength, from t0 to t1 is given by
[tex]\int_{t_0}^{t_1}\sqrt{\left(\frac{dx}{dt}\right)^2+ \left(\frac{dy}{dt}\right)^2+ \left(\frac{dz}{dt}\right)^2} dt[/tex]
 
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HallsofIvy said:
First what are Pi and Pi-1? Without knowing that we can't make any sense out of that formula. Also, where did you get that formula? I don't recognize it.
If you divide a curve into n pieces, then the arclength is the sum of the length of anyone piece which, for large n, can be approximated by the straight line between the endpoints:
sum [itex]\sqrt{((x_i- x_{i-1})^2+ (y_i- y_{i-1})^2+ (z_i- z_{i-1})^2}[/itex] and the actual arc length is the limit as n goes to infinity.


I have no idea what you mean by this. By "the function of a curve" I presume you mean something like the f(x) in y= f(x) or the vector function [itex]\vec{r}(t)= f(t)\vec{i}+ g(t)\vec{j}+ h(t)\vec{k}[/itex]. But the product of either of those by a number (the arclength) is not a number (the area). And what area are you talking about? In general, an arc does not have any "area" associated with it.


In general, if a curve in 3 dimensions is given by (x(t),y(t),z(t)), that is, as parametric functions of t, then the arclength, from t0 to t1 is given by
[tex]\int_{t_0}^{t_1}\sqrt{\left(\frac{dx}{dt}\right)^2+ \left(\frac{dy}{dt}\right)^2+ \left(\frac{dz}{dt}\right)^2} dt[/tex]

This was out of James Stewart Calculus book and I realized this just represneted a line segment it was not multiplicitive.
 

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