I'm assuming you have some knowledge of the fresnel equations, which deal with how an electromagnetic wave interacts with the interface between two media. If you don't know this, then it is much more difficult to accurately describe the Brewster angle!
Any ways, from the fresnel equations it is easy to see when the reflected portion of the electric field is zero. Trivially, there is the case where n1=n2, that is, the two media are optically identical and of course there is no reflection. The second case is the brewster angle, for which [tex]n_2 / n_1 = tan \theta_B[/tex]. Another way of thinking about this is that if you have a beam which is a mixture of polarizations parallel to and perpendicular to the interface, the reflected portion of the beam parallel is completely zero, i.e. the reflection is polarized perpendicular to the interface. Equivalently, if you shine a beam which is parallel polarized on the interface, there will be no reflected beam at all!
Does that help at all? If what I've said doesn't make sense I suggest you look back at the Fresnel equations and perhaps read the wiki article and see if you still have any questions =)