Understanding CMOS Gate States: Shoot-Through and Capacitance Effects

Click For Summary
The discussion focuses on the behavior of CMOS gate states, particularly during transitions between logical states. When input values change slowly, states such as Z or crowbarred can occur, influenced by threshold voltages. The crowbarred state, also known as "shoot-through," leads to power dissipation and supply bounce during logic transitions. This shoot-through effect can vary in significance based on the threshold and supply voltages, especially when both devices are on simultaneously. Additionally, the charging and discharging of gate and net capacitances are highlighted as major contributors to CMOS current consumption.
anhnha
Messages
179
Reaction score
1
Please help me with the question in the picture about pull-up and pull-down networks.

attachment.php?attachmentid=69451&stc=1&d=1399337661.png
 

Attachments

  • output states of general logic gate.PNG
    output states of general logic gate.PNG
    25 KB · Views: 759
Engineering news on Phys.org
If your networks are replaced with single FET's, then, in general, yes, for steady state 1 or 0 input values.

Even then though, when the input is (slowly) transitioning between 0 and 1 you can get other states (Z or crowbarred), depending on the threshold voltages.
 
Thank you. That was a bit confusing.
 
Also, you always get a crowbarred state for a short time when a logic gate is transitioning between logical states. That is where the power dissipation of CMOS comes from. It is also the source of supply bounce.
 
The short "crowbar" state during logic transitions is referred to as "shoot-through" and is only one source of CMOS current consumption and supply bounce. Another is the charging and discharging of gate and net capacitances. The Shoot-through portion of CMOS current can be very small or very significant depending on threshold and supply voltages. To the extent that the supply and thresholds are such that both devices can be on at the same time, shoot-through will be significant. But the charging and discharging on gate and net capacitances is generally a major contributer.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

Similar threads

Replies
12
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
6
Views
2K
Replies
13
Views
5K
  • · Replies 3 ·
Replies
3
Views
5K