- #1
s883
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Homework Statement
Could anyone explain me how to solve this?
Homework Equations
f(x) =
1/x2 + 4x + 9 + x4 , f’”’(-2) =
Understanding Differential Calculus: Solving Homework Equations
- Thread starter s883
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SUMMARY
The discussion focuses on solving the fourth derivative of the function f(x) = 1/x² + 4x + 9 + x⁴ at x = -2. Participants clarify that the task involves applying the power rule of differentiation to find f'(x), f''(x), and f'''(x) before calculating f''''(-2). The importance of posting calculus-related questions in the appropriate forum is also highlighted.
PREREQUISITES- Understanding of differential calculus concepts
- Familiarity with the power rule of differentiation
- Ability to compute higher-order derivatives
- Basic knowledge of evaluating functions at specific points
- Practice finding higher-order derivatives using the power rule
- Learn about the implications of evaluating derivatives at specific points
- Explore applications of differential calculus in real-world problems
- Study common mistakes in calculus to avoid errors in homework
Students studying calculus, educators teaching differential calculus, and anyone seeking to improve their skills in solving derivative-related homework problems.
Could anyone explain me how to solve this?
f(x) =
1/x2 + 4x + 9 + x4 , f’”’(-2) =
- #2
Saladsamurai
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Hello s883! 
It means to take the 4th derivative of the given function f(x) and then evaluate the resulting expression at x = -2. And I would probably put calculus questions in the calculus forum for next time 
It means to take the 4th derivative of the given function f(x) and then evaluate the resulting expression at x = -2. And I would probably put calculus questions in the calculus forum for next time - #3
HallsofIvy
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Homework Helper
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I assume you mean f(x) = 1/x^2 + 4x + 9 + x^4= x^{-2}+ 4x+ 9+ x^4.
Can you find f'(x) using the "power rule" ((x^n)'= n x^{n-1})?
What about f'' and f'''?
Now do f''''.
Can you find f'(x) using the "power rule" ((x^n)'= n x^{n-1})?
What about f'' and f'''?
Now do f''''.
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