Understanding e+e- --> W+W- Process Diagrams

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Homework Help Overview

The discussion revolves around the Feynman diagrams for the process e+e- → W+W-, focusing on the lowest-order interactions in particle physics. Participants are exploring the characteristics of s-channel and t-channel diagrams and the implications of particle interactions and conservation laws.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning why certain particles are involved in the s-channel versus the t-channel and the implications of these choices. They are also discussing the allowed vertices in particle interactions and the role of lepton number conservation in these diagrams.

Discussion Status

The conversation is ongoing, with participants providing insights into the nature of the diagrams and the rules governing particle interactions. Some guidance has been offered regarding the allowed vertices and the flow of time in the diagrams, but confusion remains regarding specific details and the rationale behind certain choices.

Contextual Notes

Participants express a lack of prior knowledge in quantum electrodynamics (QED) and are navigating the complexities of their first course in particle physics. There are references to course notes and external resources that may aid in understanding the topic better.

davon806
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Homework Statement


Hi there,
I am a very beginner in particle physics and now I'm struggling with this question.
Draw the lowest-order Feynman diagrams for e+e- --> W+W- process

Homework Equations

The Attempt at a Solution


There are 3 answers as follows:
31afc7e1-17c7-495e-9f92-248600d71349.jpg

Q1: 1st pic: Why did the gamma and Z take place in s -channel but not t -channel?
Q2: 2nd pic: Is there a reason why (e-) neutrino is the force carrier? Couldn't it be other entities like gamma or
Z or sth else?

Thanks
 

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Q1: You need the electrons going in and the Ws coming out. You can only do that with the s-channel with a photon or Z. To have the t-channel, you'd need to turn the diagram sideways, which would correspond to, for example, an electron and W+ interacting to produce the positron and W-.

Q2: There are only certain allowed vertices. You can't have an electron, W, and photon at one vertex. That would violate conservation of lepton number, for one thing.

Do you have a textbook? There's probably a page showing diagrams of the allowed vertices.
 
vela said:
Q1: You need the electrons going in and the Ws coming out. You can only do that with the s-channel with a photon or Z. To have the t-channel, you'd need to turn the diagram sideways, which would correspond to, for example, an electron and W+ interacting to produce the positron and W-.

Q2: There are only certain allowed vertices. You can't have an electron, W, and photon at one vertex. That would violate conservation of lepton number, for one thing.

Do you have a textbook? There's probably a page showing diagrams of the allowed vertices.

I am just following my lecturer's note and he didn't say when we are going to use s or t-channel.I apologize but I'm really confused since this is my first course in particle physics, and I have no previous knowledge in QED so that a lot of course notes online are too difficult for me...:sorry:

I'd like to know, if time is flowing from left to right, in both s and t channels? (1st and 2nd pic)
To me, the only difference between 1st and 2nd pic is that:
1) e- doesn't physically touch e+ in 2nd pic
2) The exchange particle is different , but I don't know why the force carrier is a neutrino ( It could also be a neutrino in 1st pic)
3) You mentioned the conservation of lepton number, so according to 2nd diagram, we now have ve,e- and W- at the lower vertex. So Le = 1 + 1 = 2
At the upper vertex,Le = 1 - 1 = 0 ?
Let say if ve is replaced by a photon, then L is still different at both vertices ( -1 and 1) ?

Sorry...Please help:frown:
 
davon806 said:
I'd like to know, if time is flowing from left to right, in both s and t channels? (1st and 2nd pic)
Yes

To me, the only difference between 1st and 2nd pic is that:
1) e- doesn't physically touch e+ in 2nd pic
2) The exchange particle is different, but I don't know why the force carrier is a neutrino ( It could also be a neutrino in 1st pic)
3) You mentioned the conservation of lepton number, so according to 2nd diagram, we now have ve,e- and W- at the lower vertex. So Le = 1 + 1 = 2
At the upper vertex,Le = 1 - 1 = 0 ?
Let say if ve is replaced by a photon, then L is still different at both vertices ( -1 and 1) ?

Sorry...Please help:frown:
Like I said in my first reply, there are only certain allowed vertices. Unless you recognize that fact, these diagrams are going to seem random to you.

Take a look at http://www.hep.phy.cam.ac.uk/~chpotter/particleandnuclearphysics/Lecture_05_FeynmanDiagrams.pdf. It may help you make sense of what's going on.
 
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