Understanding Electric Potential Concepts: Help with Multiple Choice Questions

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Homework Help Overview

The discussion revolves around understanding electric potential concepts through multiple choice questions related to capacitors, electric fields, and energy stored in capacitors. The original poster seeks assistance in verifying their answers and understanding the underlying principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods for calculating equivalent capacitance, potential differences, and energy stored in capacitors. There are attempts to clarify the relationship between electric field and potential, as well as the conditions under which work is done by the field.

Discussion Status

Some participants have provided guidance on how to approach specific problems, particularly regarding integration for potential differences and the interpretation of electric field direction. There is an ongoing exploration of the correct answers to the multiple choice questions, with some participants confirming their calculations.

Contextual Notes

Participants are working within the constraints of multiple choice questions and are encouraged to show their work for further clarification. There is a request for understanding the conditions under which work done by the field is considered positive or negative.

musicfairy
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I need some help on those multiple choice questions that I'm using to learn the concepts. Some of them I know how to do and needs someone to check my work. Other ones I need hints so I know how to start.

04e36.jpg


1. Three ½ μF capacitors are connected in series as shown in the diagram above. The capacitance of the combination is
(A) 3/2 μF
(B) 1 μF
(C) 2/3 μF
(D) 1/2 μF
(E) 1/6 μF

I used this equation: 1/Ceq = 1/C1 + 1/C2 + 1/C3 and got E as the answer.


2. In a certain region, the electric field along the x-axis is given by

E = ax + b, where a = 40 V/m2
and b = 4 V/m.

The potential difference between the origin and x = 0.5 m is
(A) -36 V
(B) -7 V
(C) -3 V
(D) 10 V
(E) 16 V


I tried to plug in 0 and 0.5 for x and subtract them but that didn't work out.


3. A 20 μF parallel-plate capacitor is fully charged to 30 V. The energy stored in the capacitor is most nearly
(A) 9x103 J
(B) 9xl0-3 J
(C) 6x10-4 J
(D) 2x10-4 J
(E) 2x10-7 J

Used the equation U = (1/2)CV2 and got B as the answer.


4. A potential difference V is maintained between two large, parallel conducting plates. An electron starts from rest on the surface of one plate and accelerates toward the other. Its speed as it reaches the second plate is proportional to
(A) 1/V
(B) 1 / √V
(C) √V
(D) V
(E) V2

qV = (1/2)mv2

When I rearrange it to isolate v it's proportional to √V so it's C.

04e48.jpg


5. A solid metallic sphere of radius R has charge Q uniformly distributed on its outer surface. A graph of electric potential V as a function of position r is shown above. Which of the following graphs best represents the magnitude of the electric field E as a function of position r for this sphere?

04e49.jpg


Electric field in a conductor is 0 and is proportional to 1/r2, so C is the answer.

04e59.jpg

This diagram is used for the next 3.

6. Which vector below best describes the direction of the electric field at point A?

04e59a.jpg


Electric field directs toward lower potential, so it's D?

7. At which point does the electric field have the greatest magnitude?

(A) A
(B) B
(C) C
(D) D
(E) E

Not sure. How do I start?

8. How much net work must be done by an external force to move a -1 μC point charge from rest at point C to rest at point E?

(A) -20 μJ
(B) -10 μJ
(C) 10 μJ
(D) 20 μJ
(E) 30 μJ

W = qV
= -1(20 - 10)
= -10 μJ

It's B.



Can someone(s) also please explain to me when is work done by field positive or negative? Thanks.
 
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E = dV/dx. So in #2 to get the V you must integrate Edx.
In #6, wouldn't it be A that points toward the lower V - perpendicular to the V line?
In #7, you want the place where the lines of constant potential are closest together so the dV/dx is highest.
 
So you mean that in #7 B is the correct answer since the potential lines are the closest?
 
Yes.
 
How do I do #2?
 
in #2 to get the V you must integrate Edx.
Use the expression you have for E and perform the integration.
If you have trouble, show your work here so we can see what is going on.
 
Ok, I see.

V = −∫E∙dr
= −ax2/2 + bx
= −20x2 − 4x

When x = 0.5
V = −7, so B is the answer.

Is this correct?
 
Yes, that's what I get.
 
Thank you for your help.
 

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