Understanding Fermi Sphere: Deriving Fermi Energy

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SUMMARY

The discussion focuses on the concept of the Fermi sphere and its relation to Fermi energy as derived in the book "Current at the Nanoscale." The key assertion is that the number of electrons, N, in a conductor is determined by the ratio of the total volume of the Fermi sphere to the volume per state. The Fermi sphere represents occupied electron states in momentum space, and its size is influenced solely by electron density, not the physical dimensions of the conductor. This understanding is crucial for studying current transfer at the quantum level.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with Fermi energy and electron states
  • Knowledge of k-space and its significance in quantum physics
  • Basic concepts of periodic boundary conditions in quantum systems
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  • Study the derivation of Fermi energy in quantum mechanics
  • Explore the concept of k-space and its applications in solid-state physics
  • Learn about the implications of electron density on Fermi sphere size
  • Investigate periodic boundary conditions and their role in quantum systems
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Students and researchers in quantum mechanics, solid-state physicists, and anyone interested in the behavior of electrons in conductors at the nanoscale.

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Hi all,

I'm studying on the current transfer at quantum level and I have a point that is not so much clear. While reading the Fermi sphere from the book "Current at the nanoscale", I could not understand the expression:

The number of electrons in the conductor, N, is the ratio of the total volume of the Fermi sphere to the volume per state

Is this sentence right, and what is its meaning? For clarity, I attached the page of the book where the author derives Fermi energy in terms of number of electrons and the volume of the conductor.

Thanks for all,
Regards
 

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It's perfectly right. The Fermi sphere is a ball in momentum space, inside which are the occupied electron states. You can calculate the number of states in k-space by assuming that your electrons are in a box of size L, with periodic or fixed boundaries. You can figure out the size of the sphere with the further information of the number of electrons in that box. You will find that the size of the sphere only depend on the density of electrons, and independent of the size of the box.
 
Just imagine that you want to fill up little boxes into a huge ball. The ball has a radius of kF while the little boxes has the sides (width, height and depth) of length equals to the periodic boundary. So the boxes will have a total volume of (periodic boundary length)^3 while the sphere will have the volume of 4/3 (pi) (kF)^3.

Both the ball and the boxes exist inside the k-space.

I attached a picture to provide the pictorial explanation. I hope this helps~
 

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