Understanding Fluid Resistance and Drag Forces in Swimming and Tug of War

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Stretching before entering the water reduces a swimmer's cross-sectional area, which decreases fluid resistance and drag forces. In tug of war, despite equal forces applied by both teams, differences in mass and friction can lead to one team winning. The discussion highlights that fluid resistance depends on factors such as viscosity, object shape, and speed. Understanding these principles is crucial for analyzing performance in both swimming and tug of war. The conversation emphasizes the importance of fluid dynamics in sports.
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Homework Statement


1) When a swimmer dives into water just before piercing himself into water, he stretches himself. Why?

2)In a tug of war if the parties on both ends of the rope apply apply equal and opposite forces on each other then how can one party win?

The Attempt at a Solution


1) I think, on stretching the body the resistance force by water on swimmer would decrease. But I cannot figure out the reason for it? Please help me.

2)I simply cannot figure out the reason. I drew the FBD's
the forces on the rope cancel out. the tension and the friction on each party is the same. But then how can a team win?
 
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ritwik06 said:

Homework Statement


1) When a swimmer dives into water just before piercing himself into water, he stretches himself. Why?

2)In a tug of war if the parties on both ends of the rope apply apply equal and opposite forces on each other then how can one party win?

The Attempt at a Solution


1) I think, on stretching the body the resistance force by water on swimmer would decrease. But I cannot figure out the reason for it? Please help me.

2)I simply cannot figure out the reason. I drew the FBD's
the forces on the rope cancel out. the tension and the friction on each party is the same. But then how can a team win?
For question (1) the only thing that I can think of it that the reaction force from the water would tend to compress the body, stretching would counteract this.

For question (2) whilst the forces may be equal, what about the masses of the teams?
 
ritwik06 said:

The Attempt at a Solution


1) I think, on stretching the body the resistance force by water on swimmer would decrease. But I cannot figure out the reason for it? Please help me.
Stretching out minimizes cross-sectional area.

2)I simply cannot figure out the reason. I drew the FBD's
the forces on the rope cancel out. the tension and the friction on each party is the same. But then how can a team win?
Is the friction force the same? Are the masses the same?
 
Doc Al said:
Stretching out minimizes cross-sectional area.
So is the resisting force cross section dependent?
 
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ritwik06 said:
So is the resisting force cross section dependent?


I am waiting for your answer sir. What kind of force is this? On what factors does it depend except for the cross section and how? Where can I read about it?
 
smaller cross sectional area=less mass of water you are hitting with the same force.
 
Look up fluid resistance or drag forces. It depends on several factors, including the nature of the fluid (viscosity), the size (cross-sectional area) and shape of the object, and the speed. There are several models used. Flip through some of these links: http://hyperphysics.phy-astr.gsu.edu/Hbase/flufri.html#c1"
 
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Doc Al said:
Look up fluid resistance or drag forces. It depends on several factors, including the nature of the fluid (viscosity), the size (cross-sectional area) and shape of the object, and the speed. There are several models used. Flip through some of these links: http://hyperphysics.phy-astr.gsu.edu/Hbase/flufri.html#c1"

Thanks a lot sir! I have got what I desired. Thanks again for solving my problem.
 
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