Understanding Force Summation and Resultant Forces on a Slab

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The discussion centers on the calculation of resultant forces acting on a slab, specifically addressing a force of 1400 N. The user correctly summed the forces to obtain -1400 N, indicating a downward force, yet questioned why the resultant force (Fr) is depicted as upward in the reference material. The consensus is that the upward representation of Fr is schematic and not indicative of the actual force direction, which is confirmed to be downward at -1400 N.

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Homework Statement


60f83f1915e83c016d92ecc2c7e13a1b.png


Find the magnitude and direction of a resultant force equivalent to the given force system and locate its point of application on the slab.

The Attempt at a Solution


So I summed the forces to get -1400 N, or a 1400 N force downward (the book agrees with that). Why is the resultant force going upward? It seems to me that they have printed a 1400 N force upward. I have no issue with the rest of the problem, but was hoping someone could explain to me why Fr is going upward.
 
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Permanence said:

Homework Statement


60f83f1915e83c016d92ecc2c7e13a1b.png


Find the magnitude and direction of a resultant force equivalent to the given force system and locate its point of application on the slab.

The Attempt at a Solution


So I summed the forces to get -1400 N, or a 1400 N force downward (the book agrees with that). Why is the resultant force going upward? It seems to me that they have printed a 1400 N force upward. I have no issue with the rest of the problem, but was hoping someone could explain to me why Fr is going upward.
It's just schematic and general. It's not meant to represent exactly the solution to this specific problem.

Chet
 
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Thank you for the response.
In the summary of the conclusion they say a Force of Fr = 1400 N is placed at P(x,y). So I assumed they wanted a positive force.
 

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