Understanding Fourier Series: Complex vs. Ordinary Coefficients

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SUMMARY

The discussion focuses on the relationship between complex coefficients and ordinary coefficients in Fourier series. It establishes that the Fourier series can be expressed using complex exponentials, specifically f(x) = Ʃcr*exp(r*2π*i*x/L). The transformation from complex coefficients (cr) to ordinary coefficients (ar and br) is clarified using Cauchy's formula, which relates the exponential form to sine and cosine functions. The discussion emphasizes that sine is an odd function and cosine is an even function, allowing for simplifications in the series representation.

PREREQUISITES
  • Understanding of Fourier series and their applications
  • Familiarity with complex numbers and exponential functions
  • Knowledge of Cauchy's formula for complex exponentials
  • Basic concepts of even and odd functions in mathematics
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  • Study the derivation of Fourier series from complex exponentials
  • Learn about the applications of Fourier series in signal processing
  • Explore the implications of even and odd functions in Fourier analysis
  • Investigate the convergence properties of Fourier series
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Mathematicians, physicists, engineers, and students studying Fourier analysis or signal processing who seek to deepen their understanding of Fourier series and their coefficients.

zezima1
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The Fourier series can also be written as:

f(x) = Ʃcr*exp(r*2π*i*x/L) where sum if from -∞ to ∞

My book says this at least, but I can't really determine the realitionship between the coefficients of an ordinary Fourier and the complex one. How do you get rid of the i that would appear in front of every sin factor, and how do you overall translate the coefficients cr to ar and br of an ordinary Fourier series?
 
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Use Cauchy's formula:
[itex]e^{2ir\pi x/L}= cos(2r\pi x/L)+ i sin(2r\pi x/L)[/itex]

Cosine is an even function and sine is an odd function so
[itex]e^{-\pi x/L}= cos(2r\pi x/L)- i sin(2r\pi x/L)[/itex]
which is why you do not need negative values of r in the sine, cosine series.

[tex]\sum_{r=-\infty}^\infty a_re^{2ir\pi x/L}= (a_r+ a_{-r}) cos(2r\pi x/L)+ (a_r- a_{-r})i sin(2r\pi x/L)[/tex]
 

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