Understanding MCAT Question Confusion: Energy and Force on Steep Hills

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Homework Help Overview

The discussion revolves around a physics problem related to energy conservation and force when a girl rides her bicycle up a steep hill using a zigzagging strategy. The participants explore the implications of gravitational potential energy and the relationship between force, distance, and energy in a conservative system.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the relationship between energy and distance traveled, particularly whether increased distance affects energy expenditure. There is also a discussion about the implications of ignoring friction and how it relates to the conservation of energy in this context.

Discussion Status

Some participants have provided insights into the nature of conservative systems and the independence of gravitational potential energy from the path taken. There is recognition of the original poster's confusion, and a few clarifications have been made regarding the principles involved, although no consensus has been explicitly stated.

Contextual Notes

Participants are operating under the assumption that friction is negligible, which frames the discussion within the context of conservative forces and energy conservation principles.

mrlucky0
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A girl riding her bicycle up a steep hill decides to save energy by zigzagging rather than riding straight up. Ignoring friction, her strategy will:

A. require the same amount of energy but less force on the pedals
B.
C.
D.

I missed this question and when I saw the correct answer, I couldn't entirely understand why the the energy remains the same. Since dE = F*D, and she has more distance to travel (to the top of the hill) shouldn't energy increase?

Edit: I understand the force is decreased by the same factor distance increases, making energy the same. But what about the increased distance to bike up the hill? Though I think I may be reading too deeply into the question making it more difficult, I'm not satisfied with the MCAT answer. Perhaps someone could correct my reasoning.
 
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Gravitational Potential Energy is independent of the path.
 
mrlucky0 said:
Edit: I understand the force is decreased by the same factor distance increases, making energy the same. But what about the increased distance to bike up the hill? Though I think I may be reading too deeply into the question making it more difficult, I'm not satisfied with the MCAT answer. Perhaps someone could correct my reasoning.

Didn't you just answer your own question?

On a side note, since you're ignoring friction, a non-conservative force, your system is a conservative system. Thus, the path one takes has no bearing on how much energy is expended to get up there. You're simply dealing with an initial energy and a final energy; in this problems case, potential energies.
 
Pengwuino said:
Didn't you just answer your own question?

On a side note, since you're ignoring friction, a non-conservative force, your system is a conservative system. Thus, the path one takes has no bearing on how much energy is expended to get up there. You're simply dealing with an initial energy and a final energy; in this problems case, potential energies.

Thanks, I've got it now. Somehow I completely overlooked the fact that, friction neglected, the system would be conservative. I mean, from a "practical" standpoint from which I based my thought process on when I encountered the question, it's just hard to believe any sane person would want to bike up a hill like that, believing they could conserve energy.
 

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