Understanding Multivariable Limits: Solving with Factoring Methods

guyvsdcsniper
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Homework Statement
Find the limit
Relevant Equations
lim(x,y)->(0,0)

I do not understand how they got the -x in the numerator to turn into a sqrt(x) when factoring to solve this multivariable function. Could some help me understand?
 
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That is not the same problem. There is a sign difference in the first term of the numerator.
 
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FactChecker said:
That is not the same problem. There is a sign difference in the first term of the numerator.
I missed that. I need to edit my post. The 1st problem in the 2nd image is what I am questioning. How did they get -x to become sqrt(x)?
 
quittingthecult said:
I missed that. I need to edit my post. The 1st problem in the 2nd image is what I am questioning. How did they get -x to become sqrt(x)?
In the work shown, ##\sqrt{xy} - x## was factored into ##\sqrt x(\sqrt y - \sqrt x)##.

Clear?
 
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Mark44 said:
In the work shown, ##\sqrt{xy} - x## was factored into ##\sqrt x(\sqrt y - \sqrt x)##.
Yea that is what's getting me. I get separating sqrt(xy) into sqrt(x)*sqrt(y). I just don't see how the -x turns into sqrt(x) when factoring.
 
Mark44 said:
In the work shown, ##\sqrt{xy} - x## was factored into ##\sqrt x(\sqrt y - \sqrt x)##.

Clear?
Oh wait. The -x is technically -x^1 and sqrt of x is technically x^1/2. so if pull a x^1/2 you are left with a x^1/2. Is that correct?
 
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quittingthecult said:
Oh wait. The -x is technically -x^1 and sqrt of x is technically x^1/2. so if pull a x^1/2 you are left with a x^1/2. Is that correct?
Why over-complicate things?
quittingthecult said:
I get separating sqrt(xy) into sqrt(x)*sqrt(y).
But you don't get separating sqrt(xx) into sqrt(x)*sqrt(x)? Edit: or ## \dfrac {x}{\sqrt x} = \sqrt x ##?

Note that we must be sure that x (and y) are non-negative for these manipulations.
 
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quittingthecult said:
Oh wait. The -x is technically -x^1 and sqrt of x is technically x^1/2. so if pull a x^1/2 you are left with a x^1/2. Is that correct?
Yes. You could also try multiplying out the factorization @Mark44 showed you and see that you recover what you started with.
 

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