Understanding Multivariable Limits: Solving with Factoring Methods

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The discussion revolves around understanding how to factor the expression ##\sqrt{xy} - x##, specifically how -x can be represented as ##\sqrt{x}## during the factoring process. Participants clarify that the expression can be factored into ##\sqrt{x}(\sqrt{y} - \sqrt{x})##, highlighting the importance of recognizing that -x is equivalent to -x^1. There is an emphasis on ensuring that x and y are non-negative to validate these manipulations. The conversation also suggests verifying the factorization by multiplying it back to confirm it matches the original expression. Overall, the focus is on clarifying the steps in the factoring process for multivariable limits.
guyvsdcsniper
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Homework Statement
Find the limit
Relevant Equations
lim(x,y)->(0,0)

I do not understand how they got the -x in the numerator to turn into a sqrt(x) when factoring to solve this multivariable function. Could some help me understand?
 
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That is not the same problem. There is a sign difference in the first term of the numerator.
 
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FactChecker said:
That is not the same problem. There is a sign difference in the first term of the numerator.
I missed that. I need to edit my post. The 1st problem in the 2nd image is what I am questioning. How did they get -x to become sqrt(x)?
 
quittingthecult said:
I missed that. I need to edit my post. The 1st problem in the 2nd image is what I am questioning. How did they get -x to become sqrt(x)?
In the work shown, ##\sqrt{xy} - x## was factored into ##\sqrt x(\sqrt y - \sqrt x)##.

Clear?
 
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Mark44 said:
In the work shown, ##\sqrt{xy} - x## was factored into ##\sqrt x(\sqrt y - \sqrt x)##.
Yea that is what's getting me. I get separating sqrt(xy) into sqrt(x)*sqrt(y). I just don't see how the -x turns into sqrt(x) when factoring.
 
Mark44 said:
In the work shown, ##\sqrt{xy} - x## was factored into ##\sqrt x(\sqrt y - \sqrt x)##.

Clear?
Oh wait. The -x is technically -x^1 and sqrt of x is technically x^1/2. so if pull a x^1/2 you are left with a x^1/2. Is that correct?
 
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quittingthecult said:
Oh wait. The -x is technically -x^1 and sqrt of x is technically x^1/2. so if pull a x^1/2 you are left with a x^1/2. Is that correct?
Why over-complicate things?
quittingthecult said:
I get separating sqrt(xy) into sqrt(x)*sqrt(y).
But you don't get separating sqrt(xx) into sqrt(x)*sqrt(x)? Edit: or ## \dfrac {x}{\sqrt x} = \sqrt x ##?

Note that we must be sure that x (and y) are non-negative for these manipulations.
 
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quittingthecult said:
Oh wait. The -x is technically -x^1 and sqrt of x is technically x^1/2. so if pull a x^1/2 you are left with a x^1/2. Is that correct?
Yes. You could also try multiplying out the factorization @Mark44 showed you and see that you recover what you started with.
 

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