Understanding Norton Current and Impedance in Point A to B Circuit

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Homework Help Overview

The discussion revolves around finding the Norton current and impedance between two points in a circuit, with references to Thevenin equivalents. Participants are exploring the relationships between these concepts and the implications of circuit parameters.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss methods for finding Thevenin and Norton equivalents, including source transformations and the conditions under which to use each theorem. Questions arise about the correctness of calculated values and the implications of specific circuit configurations.

Discussion Status

There is an ongoing exploration of the relationships between Thevenin and Norton equivalents, with some participants providing guidance on methods to approach the problem. Multiple interpretations of the circuit behavior are being considered, particularly regarding the conditions for Norton current and impedance calculations.

Contextual Notes

Participants mention specific values for components and conditions under which certain equations apply, such as the Wheatstone bridge condition. There is also discussion about the independence of certain resistances in the context of impedance calculations.

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Homework Statement


Find Norton current and impedance between points A and B.

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The Attempt at a Solution


I really don't have idea how to find impedance when points A and B are positioned like that in the diagram. And if let's say I found the impedance , when trying to look for Thevenin voltage(I don't really like norton, I always try to find U_th, speaking of it, when exactly should I use Norton instead Thevenin?), I found that Ut=0, but I don't if that's correct, neither if way of finding it was correct.
 

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You can first convert the circuit into Thevenin equivalent and then by using source transformation, convert it into Norton equivalent. I always prefer this method. Thevenin impedance value is same as that of Norton impedance, but Zth comes in series with Vth and ZN comes in parallel with IN. Are you given the values of R, XL and Xc?
 
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But I still don't understand how to find Thevenin impedance (or is my Thevenin voltage correct). I do understand how to find Norton current, but for that I need Thevenin voltage and impedance and then I_N=U_t/Z_t. But when is advisable to use Norton over Thevenin?
 
crom1 said:
But I still don't understand how to find Thevenin impedance (or is my Thevenin voltage correct). I do understand how to find Norton current, but for that I need Thevenin voltage and impedance and then I_N=U_t/Z_t. But when is advisable to use Norton over Thevenin?
As per my knowledge, a circuit which can be solved by Norton's theorem can also be solved by Thevenin's theorem. It's a matter of choice. If you are comfortable with current sources, you can choose to go with Norton. Here,they are specifically asking for Norton current. To get that, you can proceed with Norton from the beginning, or you can first develop the Thevenin equivalent and convert it into Norton. It's all up to you.
However, in some examples, you have to go with only Thevenin or Norton. But here, you have a choice.
 
How did you get Vth=0? It would be 0 only when R2=XL*Xc. What are the values of R,Xc and XL?Could you show your working?
 
If you're not working with actual component impedance values the math is probably going to get a bit messy. Be sure to have a large piece of paper handy :smile:

You can find expressions for the potentials at A and B individually, then take the difference ##V_A - V_B## to find the open-circuit potential across AB. That's your Thevenin voltage ##V_{th}##. Similarly you can place a short across AB yielding three loops. Solve for the current through the shorting wire (mesh analysis comes to mind) to yield the Norton current ##I_N##. With both of those in hand you should know how to find the Thevenin (= Norton) impedance.
 
I forgot to say U=100 V , R=XL=Xc=10 ohms. Can I conclude since this is wheatstone bridge , and R^2=Xl*Xc, that the I_N=0?
But still, I do get for thevenin voltage for A=50+j50, and B=50+j50,i.e. Ut=0?
How do I found impedance now when both of these are 0?
 
Zth is a matter of series parallel impedances. Replace the source by a short and proceed.
 
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Here's a technique that can come in handy when dealing with bridge circuits such as this.

First solve for the voltage at the top of the bridge. Let's call it V1. Use any method you're comfortable with. Looks like a natural for nodal analysis to me.:

upload_2016-1-29_10-50-59.png


Now, since both branches of the bridge are in parallel they must both have this voltage V1 across them. You can split V1 into two identical sources, each powering one of the branches:

upload_2016-1-29_10-53-0.png

Now can you find the Thevenin impedance?
 
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Yes,I do get Zt=10 ohms. One more question though, how do I justify the fact that I ignore the resistor R next to voltage source in the first picture?
 
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crom1 said:
Yes,I do get Zt=10 ohms. One more question though, how do I justify the fact that I ignore the resistor R next to voltage source in the first picture?
If you think about it, it wasn't ignored. It was taken into account when you determined V1. If that R had been different, V1 would have been different.

If the operating frequency changes or the reactances are changed, V1 will change, too.
 
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  • #12
I meant why Zt is independent of that R, but I get it now,thanks.
 

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