Understanding Operators & Observables: Averages & Variance

Feynmanfan
Messages
128
Reaction score
0
I have trouble understanding operators and observables:

Does <A> the average value of an observable and the variance depend on the state of the system? What does it have to do with the Hamiltonian?

Thanks!
 
Physics news on Phys.org
Basically none.Yes,both the variance and the expectation value/average depend upon the quantum state.

Daniel.
 
This is too general question. With respect to Hamiltonian there are two types of operators- those which commute and those which does not commute with Hamiltonian.
If we have a time independent Hamiltonian, then those operators which commute with it will have their average value constant.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

Similar threads

Replies
3
Views
1K
Replies
2
Views
1K
Replies
33
Views
3K
Replies
49
Views
8K
Replies
8
Views
1K
Replies
10
Views
4K
Replies
124
Views
8K
Replies
27
Views
3K
Back
Top