Understanding Orbital Momentum: The Mysterious Formulation Explained

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The discussion centers on the confusion surrounding the formulation of orbital momentum, specifically p = miv/(2πl) = const, and its relationship to the more familiar p = mv. Participants note that the notation used can be misleading, particularly the use of "i," which does not refer to imaginary numbers in this context. Clarification is sought regarding the dimensional consistency of the orbital momentum equation and its connection to established concepts like angular momentum. The conversation hints at possible links to Kepler's laws, but the original text's translation issues complicate understanding. Overall, the participants aim to demystify the formulation and its implications in physics.
DesertFox
Hello everybody!
I'm layman in physics, but recently I have very strong interest. Now I am struggling to obtain some knowledge all by myself. That's so complex, probably impossible for me... that's why i decided to sign up in the forum and I hope to get help from people who are versed and educated in physics.

Here is the first question which I hope to get answer...
I know about the notorious formulation: p = m x v
p - momentum;
m - mass;
v - velocity.

Two weeks ago, I read a text about "free moving (circulation) in gravitational orbit". In the text they talk about orbital momentum. The formulation of orbital momentum was presented as: p = miv/(2πl) = const
p - orbital momentum;
m - mass;
iv - orbital velocity, also: velocity of circulation (it was represented as a kind of imaginary velocity; i - imaginary unit ?)
2πl - orbital length (circumference).

I searched in the physics textbooks, which I have at home... I searched in google... but i can't find information (and explanation) about this formulation.
"p = m x v" is derived from "p = miv/(2πl)"? Or "p = miv/(2πl)" is derived from "p = m x v"?
I will be very thankful for every comment about this mysterious formulation ( p = miv/(2πl) )...

Have a nice day everybody! :approve::approve::approve:

P.S. English is not my native language, but I hope I managed to ask my questions clearly enough..
 
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Hello Fox, :welcome:

Your i has nothing to do with imaginary numbers. Check out angular momentum and perhaps it becomes clearer.

Your notation is understandable but leads to confusion: physicists use x for vector products and bold face for vectors (or an arrow above a vector quantity).
So translational momentum vector ##\vec p## is defined as ##\vec p \equiv m\vec v ##
And angular momentum ##\vec L \equiv \vec r \times \vec v## as you find in Wikipedia.

Talking about orbital momentum is confusing. Could you refer us to the precise wording or post a piece of context ?
DesertFox said:
The formulation of orbital momentum was presented as: p = miv/(2πl) = const
looks weird dimensionally: mass/time ?
 
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The original text is written in bulgarian language, so it is difficult to translate it literally.
I will try one more time to represent the question and i will make some corrections in my questions.

Here it is in short:
He (the author) talks about a free movement (circulation) in gravitational orbit and he describes the momentum like this: p = miv/(2πl) = const
p - momentum;
iv - orbital velocity (velocity of circulation);
2πl - orbital length (perimeter of circumference).

After that, he says:
when we have 2πl= i (imaginary number), we get: p = mv

I can't grasp his idea. The final formulation (p = mv) is OK, it is notorious.But his primary formulation ( p = miv/(2πl) = const )... I can't understand it...

I hope I made my question more clear and I look for help.o_O
 
Can't say it helps me understand better. ##2\pi l = i ## simply can't be meaningful to me either.

Is there a connection with the Kepler laws in the bul.. (sorry about the pun) story ?
 
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