- #1

- 1,331

- 45

## Main Question or Discussion Point

In my statistics class I am making use of permutations very often. I need to make sure I understand this.

If I have a set of 13 elements, I can arrange that 13! different ways, because Psub(13,13) = 13!/0!.

If I pick 2 elements from those 13 elements, I can get 13!/11! different results.

Is that what it means?

If I have a set of 13 elements, I can arrange that 13! different ways, because Psub(13,13) = 13!/0!.

If I pick 2 elements from those 13 elements, I can get 13!/11! different results.

Is that what it means?