- #1
- 1,342
- 41
In my statistics class I am making use of permutations very often. I need to make sure I understand this.
If I have a set of 13 elements, I can arrange that 13! different ways, because Psub(13,13) = 13!/0!.
If I pick 2 elements from those 13 elements, I can get 13!/11! different results.
Is that what it means?
If I have a set of 13 elements, I can arrange that 13! different ways, because Psub(13,13) = 13!/0!.
If I pick 2 elements from those 13 elements, I can get 13!/11! different results.
Is that what it means?