Understanding Physics Impulse: Integrated vs Average

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SUMMARY

The discussion centers on the distinction between integrated impulse and average impulse in physics, particularly in the context of force versus time curves. It highlights that the area under the force versus time curve provides a more accurate measurement of impulse compared to average calculations derived from changes in velocity. The example of the Estes A10 engine illustrates how integrated impulse accounts for rapid changes in force, which are crucial for accelerating model rockets effectively. This emphasizes the importance of understanding impulse in real-world applications, such as rocketry.

PREREQUISITES
  • Understanding of impulse in physics
  • Familiarity with force versus time graphs
  • Knowledge of momentum and its relation to impulse
  • Basic principles of rocket propulsion
NEXT STEPS
  • Study the concept of impulse in-depth, focusing on integrated versus average calculations
  • Analyze force versus time graphs in various physics scenarios
  • Explore the principles of momentum conservation in rocket launches
  • Review case studies involving Estes A10 engines and their performance metrics
USEFUL FOR

Students of physics, aerospace engineers, and hobbyists interested in model rocketry will benefit from this discussion, particularly those looking to deepen their understanding of impulse and its practical applications in propulsion systems.

dgl7
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I have a question about physics in real life. Other than the fact that the area under a force versus time curve is a more accurate way to measure impulse because it's not an average like calculating impulse from a change in velocity is, is there any other reason that the integrated impulse would differ from the average impulse? Please let me know if I have phrased this oddly and you need clarification to answer my question. Thank you!
 
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As a thought experiment, you may go to this page:

http://www.nar.org/SandT/NARenglist.shtml

Open the pdf file for the Estes A10 engine and note the impulse is the area under the curve on the second page. Draw this impulse as an average (rectangle) and the big spike goes away, which is necessary to accelerate a model rocket up to stable velocity while on the launch rail. Both curves have the same total value if you take an impulse integral! The integral of the curve with the spike will accumulates greater impulse (area) in less time initially, causing a greater change in momentum in that region.
 
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