Understanding Results from a Relativistic Star Ship Calculator

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SUMMARY

The discussion focuses on the discrepancies between user expectations and the results from the "Relativistic Star Ship Calculator" when simulating space travel under continuous acceleration at 1G. The user initially believed that traveling 10 light years at this acceleration would take approximately 2 years, but the calculator indicated a travel time of 4.9 years and a maximum speed of 0.987c. The key misunderstanding lies in the application of Special Relativity, particularly in how velocities add and the effects of Lorentz Factor on perceived speed and time during acceleration.

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  • Understanding of Special Relativity principles
  • Familiarity with the concept of Lorentz Factor
  • Knowledge of continuous acceleration and its effects on time dilation
  • Basic grasp of relativistic velocity addition
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danielgoodman
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Hello, first time poster here!

I am trying to understand some results I am getting from this "Relativistic Star Ship Calculator". This site sets up the question I'm trying to answer exactly like I imagined it should (thanks to The Forever War). From the description:

The star ship accelerates continuously from the origin to the midpoint of the mission.
At the midpoint, the ship turns its thrusters to face the destination.
The ship decelerates continuously from the midpoint to the destination.

The way I understood it, if you are accelerating at 1G and hope to come arbitrarily close to the speed of light, it should take (3*10^8 m/s)/(9.8 m/s^2)= ~354 days. Similarly, if you hope to decelerate from such a speed, it will require the same amount of time. So say about 2 years of combined acceleration/deceleration.

Further, I thought that at a velocity which is arbitrarily close to c, your Lorentz Factor becomes arbitrarily high, meaning that light years can be traveled in seconds (or less). So the conclusion I reached is that you can travel virtually any distance in ~2 years if you had a ship that accelerates at 1G and can reach a very high fraction of c.

When inputting large distances in the calculator linked above, I get results that don't fit with my rationale. Example:

Input: Distance: 10 LY
Acceleration: 1G
Output: Time: 4.9 Y
Max Speed: 0.987 c

So this calculator assumes your trip takes 4.9 Y (not 2) and you only reach 0.987 c (not .99999...c)

Can someone explain the fault in my reasoning?

Thanks so much!
 
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danielgoodman said:
The way I understood it, if you are accelerating at 1G and hope to come arbitrarily close to the speed of light, it should take (3*10^8 m/s)/(9.8 m/s^2)= ~354 days.
Velocities do not add that way. That would be true under Galilean relativity, but not Special relativity. (See: How Do You Add Velocities in Special Relativity?)

The longer the acceleration is applied, the less affect it has on the speed with respect to the original frame. (Note that the acceleration is measured from an inertial frame co-moving with the rocket at any moment--not with respect to the original frame.)

After one year (in rocket time) of accelerating at g, your speed would be only about .77c. (See: http://math.ucr.edu/home/baez/physics/Relativity/SR/rocket.html)

Further, I thought that at a velocity which is arbitrarily close to c, your Lorentz Factor becomes arbitrarily high, meaning that light years can be traveled in seconds (or less).
That's true.
So the conclusion I reached is that you can travel virtually any distance in ~2 years if you had a ship that accelerates at 1G and can reach a very high fraction of c.
The problem is that you are not going as fast as you think. It takes a while to reach a really high speed at that acceleration.
 


Thanks Doc Al, I'll read those links. I'm kind of miffed that I made it out of my Physics course (which covered special relativity) without understanding that bit. Anyway, good to know!
 

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